The solution to the system of equations is x = -1 and y = -1
<h3>How to solve the following
system of equations?</h3>
The system of equations is given as:
2x + 3y = 1
5x - 4y = 14
Multiply 2x + 3y = 1 by 2.5
So, we have:
5x + 7.5y = 2.5
Subtract 5x + 7.5y = 2.5 from 5x - 4y = 14
So, we have
7.5y + 4y = 2.5 - 14
Evaluate the difference and the sum
11.5y = -11.5
Divide by 11.5
y = -1
Substitute y = -1 in 2x + 3y = 1
2x + 3(1) = 1
This gives
2x + 3 = 1
Subtract 3
2x = -2
Divide by 2
x = -1
Hence, the solution to the system of equations is x = -1 and y = -1
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Y = 3/8(x + 4)....multiply both sides by 8/3, eliminating the 3/8 o the right
8/3y = x + 4....now subtract 4 from both sides
8/3y - 4 = x <==
n = m^2 - (n + 3)
n = m^2 -n - 3...add n to both sides
n + n = m^2 - 3
2n = m^2 - 3...add 3 to both sides
2n + 3 = m^2...take sqrt of both sides, eliminating the ^2
sqrt (2n + 3) = m or m = - sqrt (2n + 3) <==
Answer:
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The measure of an inscribed angle is half the measure of the arc it intercepts. The sum of all arcs in a circle is 360°. Inscribed angles that intercept the same arc are congruent. Pretty simple algebra and geometry. It should take you less time to work these than it does to post them.
Units period also called the hundreds period
