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bixtya [17]
3 years ago
13

It’s takes Kim 8 hours to travel a distance of 360 miles at this rate how many miles does Kim travel in 12 hours

Mathematics
1 answer:
olchik [2.2K]3 years ago
8 0

Answer:

540

Step-by-step explanation:

\frac{360}{8}  =  \frac{x}{12}  \\  \\ 45 =  \frac{x}{12}  \\  \\ 12(45 =  \frac{x}{12} ) \\  \\ x = 540

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What is the area of 8,2,5,4
jonny [76]

Multiplying all of the numbers together you'd get 320

4 0
3 years ago
3+x=x^2+3x Rewrite the equation by completing the square. What are the solutions to the equation?
Luda [366]

Answer:

hope this helps

Step-by-step explanation:

3+x=x²+3x

Simply the equations.

= x+3=x²+3x

Subtract x²+3x from both sides.

x+3−(x²+3x)=x2+3x−(x²+3x)

−x2−2x+3=0

Factor left side of equation.

(−x+1)(x+3)=0

−x+1=0 or x+3=0

Answer:

x=1 or x=−3

8 0
2 years ago
1000^m / 100^n can be written in the form of 10^z express z in terms of m and n
Julli [10]

Answer:

z = 3m - 2n

Step-by-step explanation:

\frac{ {1000}^{m} }{ {100}^{n} }  =  {10}^{z}  \\  \\  \frac{ {10}^{3m} }{ {10}^{2n} }  =  {10}^{z}   \\  \\  {10}^{3m - 2n} =  {10}^{z}  \\  \\ 3m - 2n = z \\  \\  \huge \red{ \boxed{z = 3m - 2n}}

5 0
3 years ago
Solve the equation:
PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

4\sqrt{3-\frac{1}{x} } -\sqrt{\frac{x}{3x-1} } =3\\4\sqrt{\frac{3x-1}{x} } -\sqrt{\frac{x}{3x-1} } =3\\\\put ~\sqrt{\frac{3x-1}{x}} =a\\4a-\frac{1}{a} =3\\4a^2-1-3a=0\\4a^2-4a+1a-1=0\\4a(a-1)+1(a-1)=0\\(a-1)(4a+1)=0\\a=1,-\frac{1}{4}\\

\sqrt{\frac{3x-1}{x} } =1\\3x-1=x\\3x-x=1\\2x=1\\x=\frac{1}{2}

when a=-1/4

\sqrt{\frac{3x-1}{x} } =-\frac{1}{4} \\

\frac{3x-1}{x} =\frac{1}{16} \\48x-16=x\\47x=16\\x=\frac{16}{47}

\frac{(1-2x)^2 \times (x^2-9)}{-x^2-x+6} \geq 0,\\both ~numerator ~and~denominator ~are~of~same~sign.\\\frac{(1-2x)^2(x^2-9)}{-x^2-3x+2x+6} \geq 0\\\frac{(1-2x)^2(x+3)(x-3)}{-x(x+3)+2(x+3)} \geq 0\\\frac{(1-2x)^2(x+3)(x-3)}{(x+3)(-x+2)} \geq 0\\(1-2x)^2\geq 0~(always)\\x\neq -3\\case.~1.\\both~numerator~and~denominator >0\\\frac{x-3}{-x+2} \geq 0\\x-3\geq 0\\x\geq 3\\-x+2> 0\\-x>-2\\x

case 2.

both numerator and denominator are negative.

x-3\leq 0\\x\leq 3\\-x+2\leq 0\\-x\leq -2\\x\geq 2\\solution~is~(-\infty,-3)U(-3,3]U[2,\infty)

5 0
2 years ago
Read 2 more answers
Will give lots of points & marked as brainily!!
koban [17]

Answer:

5.c= 62

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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