1.) y-7=4(x+3)
2.) y+7=(x-1)
3.) y-3=6(x+8)
We are asked for the number of <span>six-digit odd numbers that can be formed. the left-most digit should not be zero because it make the number -five digit already. An odd number ends only in 1, 3, 5, 7 and 9. Using counting, the 6th digit can only have 5 numbers, the 5th, 4th, 3rd, and 2nd can have, 10 numbers. The first number can only have 9 numbers. Hence the total number is 450,000</span>
Answer:
2
A)-7y^3-3y^2-2y-8
B)-7x^3y^3-12x^2y^2-xy
C)2xy^3+3xy^2-5
3
A)14x^2
B)15a^2+30ab
Step-by-step explanation:
Answer: 8 buses
Step-by-step explanation:
You need 8 buses minimum
