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Scorpion4ik [409]
3 years ago
9

1.

Mathematics
1 answer:
Mama L [17]3 years ago
3 0

Answer: x=25, y=19

Step-by-step explanation: Because the triangle is equilateral, all the angles must be equal to 60 degrees. So 2x+10=60. 2x=50 and x=25. Then the same thing: 3y+3=60. 3y=57, y=19.

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It costs $15 to send 3 packages through a certain shipping company. Consider the number of packages per dollar. a. Find the cons
Contact [7]

x is the number of packs 3x=15$ x=5$

6 0
3 years ago
What's the answer to x÷6=-13
Mariulka [41]

To find this answer :

Step 1: Simplify both sides of the equation.

1/6x=-13

Step 2: Multiply both sides by 6.

6*(1/6x)=(6)*(-13)

You will get x=-78.

8 0
4 years ago
David invested $1,000 what would that money grow to in 18 months at a 5.5% interest rate
Nataly [62]
Interest I  =  PRT /100     

P = $ 1000
R = 5.5% per annum
T = 18 months  = 18 /12 = 1.5 years.

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Amount = P + I  =  1000 + 82.5 = 1082.5.

Hence the it would have grown to $1082.5
4 0
3 years ago
Allelogram.<br> 7.<br> 18<br> U<br> T<br> x + 1<br> S<br> V<br> 3x - 3<br> –<br> 5<br> Answer:
Talja [164]

Answer: canada is the 2nd biggest country. It sucks.

Step-by-step explanation:

4 0
3 years ago
A man rides a bicycle a distance of 48 miles in a certain amount of time. If the man increased his speed by 2 miles per hour, he
seropon [69]
Recall your d = rt, distance = rate * time.

so, in his usual speed, say is hmm "r" mph, so in his usual "r" speed, he rolls on for the 48 miles and it takes him "t" hours to get there.

now, if he increases his speed by 2 mph, then his new speed is "r + 2", and he arrives there 4 hours earlier, so if he took "t" hours going at "r" speed, then when he's going faster at "r + 2", he only takes "t - 4" hours, for the same 48 miles.

\bf \begin{array}{lccclll}&#10;&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\&#10;&------&------&------\\&#10;\textit{usual speed}&48&r&t\\&#10;\textit{faster speed}&48&r+2&t-4&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;48=rt\implies \frac{48}{r}=\boxed{t}\\&#10;48=(r+2)(t-4)\\&#10;----------\\&#10;48=(r+2)\left( \boxed{\frac{48}{r}}-4 \right)&#10;\end{cases}&#10;\\\\\\&#10;48=(r+2)\left( \cfrac{48-4r}{r} \right)\implies 48r=(r+2)(48-4r)&#10;

\bf 48r=48r-4r^2+96-8r\implies 0=-4r^2+96-8r&#10;\\\\\\&#10;4r^2+8r-96=0\implies r^2+2r-24=0&#10;\\\\\\&#10;(r+6)(r-4)=0\implies r=&#10;\begin{cases}&#10;-6\\&#10;\boxed{4}&#10;\end{cases}

it cannot be a negative value, since is just a forward speed rate, so can't be -6.
8 0
3 years ago
Read 2 more answers
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