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Assoli18 [71]
3 years ago
6

Evaluate y = ex + 1 for the following values of x. Round to the nearest thousandth. x = −2, y ≈ x = 1, y ≈ x = 2, y ≈

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
4 0
The equation is not clear whether it is y= e^{x+1} or y= e^{x} +1

for y= e^{x+1}

x=-2 ⇒ e^{-2+1}=0.37
x=1 ⇒ e^{-1+1} = e^{0}=1
e^{2+1}= e^{3}=20.10

for y= e^{x}+1

x=-2⇒y=e^{-2}+1 =1.14
x=1⇒y= e^{1} +1=3.72
x=2⇒y= e^{2}+1=8.39

Hint: Most scientific calculators have the template of e^{( )} which you can use to work out the value of y
Brilliant_brown [7]3 years ago
4 0

1.135, 3.718, 8.389

Graph: B

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The sides of ∆ABC are 30 units, 40 units, and 60 units long. The corresponding sides of ∆XYZ are r times as long as the sides of
san4es73 [151]

Part a) Find the expression that gives the perimeter of ∆XYZ

we know that

Perimeter of triangle ABC is equal to

P=30+40+60\\ P=130\ units

In this problem ∆ABC and ∆XYZ are similar triangles

the scale factor is equal to r

so

scale\ factor=r \\ \\ scale\ factor=\frac{perimeter\ triangle\  XYZ}{perimeter\  triangle\  ABC}  \\ \\ perimeter\ triangle\  XYZ=perimeter\  triangle\  ABC*scale factor\\ \\ perimeter\ triangle\  XYZ=130*r

therefore

the answer Part a) is

The expression that gives the perimeter of ∆XYZ is 130*r\ units

Part b) Find the expression that gives the area of ∆XYZ

we know that

Area\ of\ triangle\ ABC=n\ units^{2}

scale\ factor=r \\ \\ scale\ factor^{2}=\frac{Area\ triangle\  XYZ}{Area\  triangle\  ABC}  \\ \\ Area\ triangle\  XYZ=Area\  triangle\  ABC*scale factor^{2}\\ \\ Area\ triangle\  XYZ=n*r^{2}\ units^{2}

therefore

the answer Part b) is

The expression that gives the Area of ∆XYZ is n*r^{2}\ units^{2}

3 0
3 years ago
Read 2 more answers
What is the period of the sinusoidal function
rodikova [14]

Answer:

The period of the sine curve is the length of one cycle of the curve. The natural period of the sine curve is 2π. So, a coefficient of b=1 is equivalent to a period of 2π. To get the period of the sine curve for any coefficient b, just divide 2π by the coefficient b to get the new period of the curve.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A botanist wishes to estimate the mean number of seeds for a certain fruit. She samples 11 specimens and finds the average numbe
Aliun [14]

Answer:

a)The 98% of confidence intervals are

Lower bound of CI = 47 -3.82436 = 43.1756

Upper bound of CI = 47 + 3.82436 = 50.8243

b) The conditions are required for the validity of the interval

A) μ known

Step-by-step explanation:

<u>Explanation</u>:-

The given sample size is 'n' =11

Given the average number of seeds is 47 with a standard deviation of 7

Sample mean (x⁻) = 47

Standard deviation (S) = 7

<u>The 98% of confidence intervals are</u>

(x^{-} - t_{0.02} \frac{S}{\sqrt{n} } , x^{-} + t_{0.02}\frac{S}{\sqrt{n} } )

(47 - t_{0.02} \frac{7}{\sqrt{11} } , 47+ t_{0.02}\frac{7}{\sqrt{11} } )

The degrees of freedom = n-1 =11-1 =10

t₀.₀₂= 1.812 ( from t - table)

now the intervals are

(47 - 1.812 \frac{7}{\sqrt{11} } , 47+ 1.812\frac{7}{\sqrt{11} } )

<u>Lower bound of CI = 47 -3.82436 = 43.1756</u>

<u>Upper bound of CI = 47 + 3.82436 = 50.8243</u>

The conditions are required for the validity of the interval

<u>A) μ known</u>

<u>Explanation</u>:-

If a random sample xi of size 'n' has been drawn from a normal population with a specified mean (μ) known.

The limit for  (μ)  is given by

(x^{-} - t_{0.02} \frac{S}{\sqrt{n} } , x^{-} + t_{0.02}\frac{S}{\sqrt{n} } )

5 0
3 years ago
What is 5.75% of $6,000
Neko [114]
$345 is 5.75% of $6,000                                                                         
3 0
3 years ago
In a school of 1800 students, the ratio of teachers to students is 1:20. Some teachers join the school and the ratio changes to
blagie [28]

Answer:

10 teachers

Step-by-step explanation:

Looking at the data provided, we can conclude that for 1800 students, there are 90 teachers.

1:20

When more teachers arrive, it then becomes, for every 1800 students, there are 100 teachers.

1:18

10 more teachers have now joined the school.

4 0
4 years ago
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