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Black_prince [1.1K]
3 years ago
14

What is the value of the expression? 8 1/2-2+4 3/4

Mathematics
1 answer:
kodGreya [7K]3 years ago
7 0
11 1/4 or 11.25 is the answer
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At camp last summer, the ratio of boys to girls was 5:4. If there was a total of 90 campers, how many girl campers are there? ex
LekaFEV [45]

Answer:

40 girls

Step-by-step explanation:

if you multiply 5 times 10, then you have to multiply the other side by 10 too. So 5 times 10 equals 50, and 4 times 10 equals 40.

40+50+=90.

4 0
3 years ago
How much more? To the nearest tenth, it holds __ cubic centimeters more than the other glass.
Andreyy89

Answer:

Two more cm. ALl you need to do now is convert it to cubic cm because I do not know how to do that.

Step-by-step explanation:

4 0
2 years ago
There are 2 green,5 yellow, 6 red,and 7 blue marbles in a bag. Erin picks one marble from the bag without looking. What is the p
Svetach [21]

Answer:

c 35%

Step-by-step explanation:

2 green,5 yellow, 6 red,and 7 blue marbles

2+5+6+7 = 20 marbles

P(blue) = blue marbles / total marbles

             = 7/20

              = 35/100

               =35%

7 0
3 years ago
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate a 5 8 per hour, so that the number o
timurjin [86]

Answer:

(a) P (X = 6) = 0.12214, P (X ≥ 6) = 0.8088, P (X ≥ 10) = 0.2834.

(b) The expected value of the number of small aircraft that arrive during a 90-min period is 12 and standard deviation is 3.464.

(c) P (X ≥ 20) = 0.5298 and P (X ≤ 10) = 0.0108.

Step-by-step explanation:

Let the random variable <em>X</em> = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, <em>λ</em>t = 8 per hour.

(a)

For <em>t</em> = 1 the average number of aircraft arrival is:

\lambda t=8\times 1=8

The probability distribution of a Poisson distribution is:

P(X=x)=\frac{e^{-8}(8)^{x}}{x!}

Compute the value of P (X = 6) as follows:

P(X=6)=\frac{e^{-8}(8)^{6}}{6!}\\=\frac{0.00034\times262144}{720}\\ =0.12214

Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

P(X\geq 6)=1-P(X

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

P(X\geq 10)=1-P(X

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For <em>t</em> = 90 minutes = 1.5 hour, the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 1.5=12

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

SD=\sqrt{\lambda t}=\sqrt{12}=3.464

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For <em>t</em> = 2.5 the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 2.5=20

Compute the value of P (X ≥ 20) as follows:

P(X\geq 20)=1-P(X

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

Compute the value of P (X ≤ 10) as follows:

P(X\leq 10)=\sum\limits^{10}_{x=0}(\frac{e^{-20}(20)^{x}}{x!})\\=0.01081\\\approx0.0108

Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

8 0
3 years ago
Question ^^<br><br><br> Give the answer with the appropriate unit of measure.
borishaifa [10]

Answer:

-11

Step-by-step explanation:

-1-10=-11

If by difference, the question means subtraction, then the answer is -11. If they mean the distance between, then the answer is 9

3 0
3 years ago
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