Answer:
Correct option is A
Since it is an equilateral triangle, the lengths of the sides are equal
So, x+3 y=3 x+2 y−2=4 x+
2
1
y+1
x+3 y=3 x+2 y−2
y=2 x−2
2 x−y=2 ...(1)
Also, 4 x+
2
1
y+1=x+3 y
8 x+y+2=2 x+6 y
6 x+2=5 y
6 x−5 y=−2 ...(2)
Multiplying e q(1) by 5 we get,
10 x−5 y=10 ...(3)
Subtracting e q(2) from e q(3) we get,
4 x=12⇒x=3
y=2 x−2=4
The length of one side of equilateral triangle = x+3 y =3+3(4)=15 units
Answer:
375
Step-by-step explanation:
Answer:
Step-by-step explanation:
The First Question !
This is simple,
So first we set this problem up
2 Red + 3 Blue + 7 Green = 12 Total Marbles
The formula for calculator probability is
# of favorable outcomes / # of possible outcomes
The number of favorable outcomes we have is 3 because we are trying to find the probability of pulling out a blue marble
The number of possible outcomes is 12 because we have 12 total marbles
3/12 simplifies to 1/4 which is .25
The probability of drawing a blue marble is 0.25 or 25%
Second Question!
The probability of getting heads on the toss of a coin is 0.5. If we consider all possible outcomes of the toss of two coins as shown, there is only one outcome of the four in which both coins have come up heads, so the probability of getting heads on both coins is 0.25. The second useful rule is the Sum Rule.
I Hope It's Helpful :0
Answer:
Part 5) The roots are x=-3 and x=1.5
Part 6) The solution on a number line is the shading area below of the line y=-1/3 (close circle)
Step-by-step explanation:
Part 5) Find the roots of the parabola given by the following equation
we know that
The formula to solve a quadratic equation of the form 
is equal to
in this problem we have
so
substitute in the formula
therefore
The roots are x=-3 and x=1.5
Part 6) Solve the inequality and graph the solution on a number line.
Solve for y
Subtract 12 both sides
Multiply by -1 both sides
Divide by 15 both sides
The solution is the interval -----> (-∞, -1/3]
All real numbers less than or equal to negative one third
The solution on a number line is the shading area below of the line y=-1/3 (close circle)
The graph in the attached figure
