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aliya0001 [1]
3 years ago
7

Mary spent half of her allowance going to the movies. She washed the family car and earned 6 dollars. What is her weekly allowan

ce if she ended with 15 dollars ?
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0
X is her allowance

X/2 + 6 = 15

X/2=11
X=22
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5. Jada is making circular birthday invitations for her friends.
Novosadov [1.4K]

Answer:

Step-by-step explanation:

Jada is making circular invitations

we have d=12 cm, the radius r=6

she needs to find out the circumference

C=2x3.14x r

C=2x 3.14x6=37.68

180/37.68=4.77

she can make just 4 invitations

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3 years ago
Y varies inversely with x y = 132 when x = 6 What is the value of k, the constant of inverse variation?
malfutka [58]
The answer to this question is i think a or b.
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You begin solving the equation 3+4x=513+4x=51 by subtracting 33 from both sides. Which is the best choice for Step 22?
bonufazy [111]
33 +4x = 513
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Answer
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7 0
3 years ago
The Perimeter Of A Parallelogram Is 72 Meters. The Width Of The Parallelogram Is 4 Meters Less Than It’s Length. Find The Length
saul85 [17]

The width would be x-4 and  

Length would be x  

Add all of the sides together  

(x-4)+(x-4) + x + x =72,

Which would come out

4x-8=72

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Then divided 64 by 4

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5 0
3 years ago
One supplementary angle is 15 degrees less than twice the other. Find the measure of the two supplementary angles.
Scilla [17]

Answer:

The measure of the two supplementary angles are 65 degrees and 115 degrees.

Step-by-step explanation:

The sum of supplementary angles is equal to 180 degrees. Let x and y are two angles such that,

x+y=180\ ....(1)

According to given condition,

One supplementary angle is 15 degrees less than twice the other, it means,

x=2y-15\ .....(2)

Putting the value of x from above equation in equation (1),

2y-15+y=180\\\\3y-15=180\\\\3y=195\\\\y=\dfrac{195}{3}\\\\y=65^{\circ}

Now put the value of y in equation (1), so,

x+65=180\\\\x=115^{\circ}

So, the measure of the two supplementary angles are 65 degrees and 115 degrees.

3 0
3 years ago
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