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Fudgin [204]
4 years ago
14

Solve R = 1+30 for w Please help I have a test tomorrow and this is a study guide

Mathematics
1 answer:
skelet666 [1.2K]4 years ago
5 0

Answer:

8 cause ur adding 3 and 1 to get 4 then multiplying by 2 and u get 8. Hope this helps bye!

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Write and solve a word problem that can be modeled by addition of two negative integers.
vitfil [10]

Answer:

Step-by-step explanation:

Question:

Max needs to purchase a car and  withdraws $100 from his bank. In a few days he withdraws another $50 to make same repairs. In total what is the change in his bank balance from theese two costs?

Solution:

(-100) + (-50) =

-150

Answered by G a u t h m a t h

3 0
3 years ago
You're having dinner at a restaurant that serves 5 kinds of pasta (spaghetti, bow ties, fettuccine, ravioli, and macaroni) in 4
Artemon [7]
You have 5 types of pasta and 4 flavors, 5*4=20, and one choice, 1/20 One over twenty, and I think that your answer is nineteen over twenty 19/20. Sorry if I am wrong. Forgive me.
8 0
3 years ago
Read 2 more answers
PLZ NEED HELP ASAP SHOW WORK TO PLZ IT WOULD MEAN A LOT
Marizza181 [45]

First Chart: Perimeter

Square Portion:

Original Side Lengths: P = 4  (1 + 1 + 1 + 1 ) =4

Double Side Lengths: P = 8 (2 x 4 = 8)

Triple Side Lengths: P = 12  (4 x 3 = 12)

Quadruple Side Lengths: P = 16 (4 x 4 = 16)

Rectangle Portion:

Original Side Lengths: P = 6 (1 x 2 + 2 x 2 = 6)

Double Side Lengths: P = 12 (2 x 2 + 4 x 2 = 12)

Triple Side Lengths: P = 24  (4 x 2 + 8 x 2 = 24)

Quadruple Side Lengths: P = 48 (8 x 2 + 16 x 2 = 48)

Second Chart: Area

Square Portion:

Original Side Lengths: A = 1 (1 x 1 = 1)

Double Side Lengths: A = 4 (2 x 2 = 4)

Triple Side Lengths: A = 9 (3 x 3 = 9

Quadruple Side Lengths: A = 16 ( 4 x 4 = 16)

Rectangle Portion:

Original Side Lengths: A = 2 ( 1 x 2 = 2 )

Double Side Lengths: A = 8 ( 2 x 4 = 8)

Triple Side Lengths: A = 18 ( 3 x 6 = 18)

Quadruple Side Lengths: A = 32 (4 x 8 = 32)

7 0
3 years ago
Please help me and I will thank you
uysha [10]

The value a = 4 will always yield a correct answer.

We know this by solving for a. If we do this, we will get the number needed.

a(x + 3) < 5x + 15 - x -----> simplify like terms

a(x + 3) < 4x + 15 -----> divide by x + 3

a < 4 + 3/(x + 3)

Since a is less than 4 plus a number, we know that a will always be less than 4. So we can use 4 as the number for all real solution.

6 0
3 years ago
Consider WXY and BCD with X= C, WX = BC, and WY = BD. Can it be concluded that WXY = BCD by SAS?
rosijanka [135]

Answer:

nswer:- B. No, because the corresponding congruent angles listed are not the included angles. Given:- ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD. We can see that ∠X and ∠C are not included angles by the corresponding equal sides.

6 0
3 years ago
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