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ycow [4]
3 years ago
7

Given the graphed function below, which of the following ordered pairs are found on the inverse function?

Mathematics
2 answers:
Dmitrij [34]3 years ago
4 0

Answer:

Its C (-9,-2)(-2,-1)(-1,0)(0,1)(7,2)

Step-by-step explanation:

fomenos3 years ago
4 0

Answer:

Step-by-step explanation:

Answer with explanation:

Suppose, y=√x ,is a polynomial function.Here Domain =[0,∞)

→ y²=x

Range =(-∞,∞)

To find the inverse of the given function,replace x by y, and y by x in the original function.

So, x=√y, is the equation of inverse function.

if a point (x,y) lies on original function, then point (y,x) lies on the inverse function.

The graphed function given below passes through points

(1,0),(0,-1),(-2,-9),(2,7),and (-1,-2).

So, inverse function of the above function will pass through

(0,1),(-1,0),(-9,-2),(7,2),and (-2,-1).

→→Option C

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ivanzaharov [21]

Answer:

y = 3x - 2 (smaller y-intercept)

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Step-by-step explanation:

First let's write the generic equation of a line:

y = ax + b

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The line 3x - y + 5 = 0 has a slope of 3, so our line has a = 3:

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Now we need to find the values of b that make this line tangent to the function f(x) = x^3

Let's first find the derivative of f(x) in relation to x:

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This derivative is the slope of the tangent line to the function for any value of x. We need a slope of 3, so:

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Now, to find the y-values, we have:

f(1) = 1^3 = 1

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So, using the points (1,1) and (-1,-1) in our parallel line, we have:

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second line using (-1,-1) : -1 = -3*1 + b

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multiply both sides by y

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