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Effectus [21]
3 years ago
14

Use the power reducing formula to rewrite the expression in therms of first powers of hte cosines of ultiple angles 3cos^4x.

Mathematics
1 answer:
Oxana [17]3 years ago
7 0

The particular identity you want to use is

\cos^2x=\dfrac{1+\cos(2x)}2

Then

3\cos^4x=3(\cos^2x)^2=3\left(\dfrac{1+\cos(2x)}2\right)^2=\dfrac34(1+\cos(2x))^2

Expand the binomial to get

3\cos^4x=\dfrac34\left(1+2\cos(2x)+\cos^2(2x)\right)

Use the identity again to write

\cos^2(2x)=\dfrac{1+\cos(4x)}2

and so

3\cos^4x=\dfrac34\left(1+2\cos(2x)+\dfrac{1+\cos(4x)}2\right)

3\cos^4x=\dfrac38\left(3+4\cos(2x)+\cos(4x)\right)

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What is the value of the product (3 - 21(3 + 21)? 2 05 O 9 + 4 9 - 41​
olasank [31]

Answer:

556

Step-by-step explanation:

8 0
3 years ago
please ingore wirthing im struggleing and thats all that is but i need help i didnt catch range and i cant figure it out
dimulka [17.4K]

Hello from MrBillDoesMath!


Answer:    

       Domain restriction:  -3  <= x <= 0

       Range restriction:    -4 <= y <= 0

Discussion

These numbers came directly from the graph. I am assuming the endpoints such as x = -3 are included in the domain.

Regards, MrB

6 0
3 years ago
House of Mohammed sells packaged lunches, where their finance department has established a
blagie [28]

The revenue function is a quadratic equation and the graph of the function

has the shape of a parabola that is concave downwards.

The correct responses are;

  • (a) <u>R = -x² + 82·x</u>
  • (b) <u>$1,645</u>
  • (c) The graph of <em>R</em> has a maximum because the <u>leading coefficient </u>of the quadratic function for <em>R</em> is negative.
  • (d)  <u>R = -1·(x - 41)² + 1,681</u>
  • (e) <u>41</u>
  • (f) <u>$1,681</u>

Reasons:

The given function that gives the weekly revenue is; R = x·(82 - x)

Where;

R = The revenue in dollars

x = The number of lunches

(a) The revenue can be written in the form R = a·x² + b·x + c by expansion of the given function as follows;

R = x·(82 - x) = 82·x - x²

Which gives;

  • <u>R = -x² + 82·x </u>

<em>Where, the constant term, c = 0</em>

(b) When 35 launches are sold, we have;

x = 35

Which by plugging in the value of x = 35, gives;

R = 35 × (82 - 35) = 1,645

  • The revenue when 35 lunches are sold, <em>R</em> = <u>$1,645</u>

(c) The given function for <em>R</em> is R = x·(82 - x) = -x² + 82·x

Given that the leading coefficient is negative, the shape of graph of the

function <em>R</em> is concave downward, and therefore, the graph has only a

maximum point.

(d) The form a·(x - h)² + k is the vertex form of quadratic equation, where;

(h, k) = The vertex of the equation

a = The leading coefficient

The function, R = x·(82 - x), can be expressed in the form a·(x - h)² + k, as follows;

R = x·(82 - x) = -x² + 82·x

At the vertex, of the equation; f(x) = a·x² + b·x + c,  we have;

\displaystyle x = \mathbf{-\frac{b}{2 \cdot a}}

Therefore, for the revenue function, the x-value of the vertex, is; \displaystyle x = -\frac{82}{2 \times (-1)} = \mathbf{41}

The revenue at the vertex is; R_{max} = 41×(82 - 41) = 1,681

Which gives;

(h, k) = (41, 1,681)

a = -1 (The coefficient of x² in -x² + 82·x)

  • The revenue equation in the form, a·(x - h)² + k is; <u>R = -1·(x - 41)² + 1,681</u>

(e) The number of lunches that must be sold to achieve the maximum revenue is given by the x-value at the vertex, which is; x = 41

Therefore;

  • The number of lunches that must be sold for the maximum revenue to be achieved is<u> 41 lunches</u>

(f) The maximum revenue is given by the revenue at the vertex point where x = 41, which is; R = $1,681

  • <u>The maximum revenue of the company is $1,681</u>

Learn more about the quadratic function here:

brainly.com/question/2814100

6 0
3 years ago
A quiz consists of 20 multiple-choice questions find mean and standard deviation
worty [1.4K]

Since the problem is quite vague because the number of choice per question is not written here. I’ll just put for 4 choices and 5 choices each.

To compute for the 5 choices each:

Mean = np = 20 (1/5) = 4

Standard deviation = sqrt(npq) = sqrt (4*(4/5) = 1.79

 

To compute for the 4 choices each:

Mean = np = 20 (1/4) = 5

Standard deviation = sqrt(npq) = sqrt (5*(4/5) = 2

4 0
3 years ago
5. Decide whether each equation is true for all, one, or no values of x.
S_A_V [24]
C doesn’t have a value , x equals 0 , x=0
6 0
3 years ago
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