Meaning of the x and y intercept what they represent

1 answer:

3 0

The x-intercept is the x-coordinate of a point where a graph intersects the x-axis and the y-intercept is the y-coordinate of a point where a graph intersects the y-axis. For example, (-4,0) -4 is the x-intercept and (0,6) 6 is the y-intercept

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A driver drives to school along the same routine Monday through Friday. There is one traffic light on her route . The probabilit

andrey2020 [161]

Answer:

0.525%

Step-by-step explanation:

Since we are trying to find the probability of a sequence of events we simply need to multiply the probability of each of these events happening separately from one another. We are told that the probability that the light will be red is 65% that means that the probability that it will be green and that the driver will not need to stop is 35%. This probability remains the same every day of the week. Therefore we need to multiply this probability 5 times, one time for each weekday Monday through Friday, but first we need to turn this percentage into a decimal form by dividing it by 100...

35% / 100 = 0.35

0.35 * 0.35 * 0.35 * 0.35 * 0.35 = 0.00525 ...multiply by 100 to get percentage

0.00525 * 100 = 0.525%

Finally, we can see that the probability that she will not have to stop at the light all next week is 0.525%

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Irina-Kira [14]

The answer is C, as it is the only one that makes sense

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3 years ago

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The rectangle below has an area of x2 + 11x + 28 square meters and a length of 2 + 7 meters.

Troyanec [42]

<h3><u>Question:</u></h3>

The rectangle below has an Área of x^2 + 11x + 28 square meters and a length of x+7 meters. What expression represents the width of the rectangle?

<h3><u>Answer:</u></h3>

The expression representing width of rectangle is (x + 4) meters

<h3><u>Solution:</u></h3>

Given that rectangle has an area x^2 + 11x + 28 square meters and a length of x + 7 meters

To find: width of the rectangle

<em><u>The area of rectangle is given as:</u></em>

$\text {Area of rectangle }=\text { length } \times \text { width }$

Here area = x^2 + 11x + 28 square meters

length = x + 7 meters

<em><u>Substituting the values in given formula,</u></em>

$\begin{array}{l}{\text { width }=\frac{x^{2}+11 x+28}{x+7}} \\\\ {\text { width }=\frac{x^{2}+4 x+7 x+28}{x+7}} \\\\ {\text { width }=\frac{x(x+4)+7(x+4)}{x+7}} \\\\ {\text { width }=\frac{(x+4)(x+7)}{x+7}}\end{array}$