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valkas [14]
4 years ago
5

What is 37.50 rounded to the nearest tenth?

Mathematics
2 answers:
photoshop1234 [79]4 years ago
6 0
37.50 rounded to the nearest tenth is 37.5
Maslowich4 years ago
3 0
I hope you're kidding but, the answer is 37.5
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WILL GIVE A CROWN...A polygon is shown: A polygon MNOPQR is shown. The top vertex on the left is labeled M, and rest of the vert
strojnjashka [21]

The area of polygon MNOPQR = Area of a rectangle that is 15 square units + Area of a rectangle that is 2 square units.

In the given polygon MNOPQR, side MN is parallel to side RQ and the side MR is parallel to side PQ

We will draw a perpendicular line from point O on the side RQ, which will intersect RQ at point S. So, we can now divide the whole polygon into two different rectangles MNSR and OPQS with the areas as A₁ and A₂ respectively.

In rectangle MNSR, length(MN) = 5 units and width (MR) = 3 units

According to the formula for Area of rectangle,

A₁ = (length)×(width)

A₁ = (5 units)×(3 units)

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Now in rectangle MNSR, side MN= side RS and side MR = side NS,

so RS= 5 units and NS= 3 units

That means, SQ= RQ- RS = 7-5 = 2 units

and OS= NS - NO = 3- 2 = 1 unit

In rectangle OPQS, we have length(SQ) = 2 units and width(OS) = 1 unit

So, A₂ = (length)×(width)

A₂ = (2 units)×(1 unit)

A₂ = 2 square units

So, the area of polygon MNOPQR = (Area of a rectangle that is 15 square units + Area of a rectangle that is 2 square units)

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