Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
To learn more on velocities: brainly.com/question/18084516
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I believe the answer is B.
Answer:
x = 2.
Step-by-step explanation:
5[3(x + 4) − 2(1 − x)] − x − 15 = 14x + 55
5[3x + 12 - 2 + 2x] - x - 15 = 14x + 55
5[5x + 10] - x - 15 = 14x + 55
25x + 50 - x - 15 = 14x + 55 Now we subtract 14x from both sides:
25x + 50 - x - 15 - 14x = 14x - 14x + 55
10x + 50 - 15 = 55 Now we subtract 50, add 15 to both sides:
10x + 50 - 50 - 15 + 15 = 55 - 50 + 15
10x = 20
x = 2.
Range should be (-∞ , 10]
answer is C.
If x is 0 then I think it would be the 3 to the second power and that is 9. Because 0 + 9 = 9. Correct me if I’m wrong!
