The correct answer is: x = ![\pm 4](https://tex.z-dn.net/?f=%20%5Cpm%204%20)
Explanation:
Given equation:
![4x^2 = 64](https://tex.z-dn.net/?f=%204x%5E2%20%3D%2064%20)
Divide both sides by 4:
![\frac{4x^2}{4} =\frac{64}{4} \\ x^2 = 16](https://tex.z-dn.net/?f=%20%5Cfrac%7B4x%5E2%7D%7B4%7D%20%3D%5Cfrac%7B64%7D%7B4%7D%20%20%5C%5C%20x%5E2%20%3D%2016%20)
Take square-root on both sides:
![\sqrt{x^2} = \sqrt{16} \\ x = \pm4](https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%5E2%7D%20%3D%20%20%5Csqrt%7B16%7D%20%5C%5C%20x%20%3D%20%5Cpm4%20%20)
Hence the correct answer is: x = ![\pm 4](https://tex.z-dn.net/?f=%20%5Cpm%204%20)
Answer:
4.
Step-by-step explanation:
(sec α - tan α)(sec α + tan α) = sec^2 α - tan^2α
But sec^2 α = 1 + tan^2 α so
sec^2 α - tan^2α = 1 + tan^2 α - tan^2α
= 1
so 1 = (sec α - tan α)(sec α + tan α) = 1/4 * x where x is sec α + tan α
1/4 * x = 1
x = 4.
It would be D because in an absolute value u cant have any negative numbers unless its on the outside, since this one doesn't have a negative sign on the outside it would have to be pointing upward. And it says that its the absolute value of x minus 7 which means the graph moves down 7.
Answer:
The answer is milligram, glad to help
Step-by-step explanation: