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Zina [86]
3 years ago
7

Please enter the missing number: 2, 9, 20, 37, 64, 107, ?

Mathematics
1 answer:
k0ka [10]3 years ago
4 0
174 is the missing number
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There are 1,500 trees in a forest, of which 300 are oak trees. What percent, p, of the trees are oak trees? Complete the stateme
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d0nt know….

Step-by-step explanation:

But hi!

3 0
3 years ago
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Determine the slope of the line that contains the given points.
nydimaria [60]

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slope = 2/3

Step-by-step explanation:

6 0
3 years ago
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A light source is located over the center of a circular table of diameter 4 feet. (See picture below) Find the height h of the l
Alex
Very nice to have an accompanied image!Illumination is proportional to the intensity of the source, inversely proportional to the distance squared, and to the sine of angle alpha.so that we can writeI(h)=K*sin(alpha)/s^2 ................(0)where K is a constant proportional to the light source, and a function of other factors.
Also, radius of the table is 4'/2=2', therefore, using Pythagoras theorem,s^2=h^2+2^2 ...........(1), and consequently,sin(alpha)=h/s=h/sqrt(h^2+2^2)..............(2)
Substitute (1) and (2) in (0), we can writeI(h)=K*(h/sqrt(h^2+4))/(h^2+4)=Kh/(h^2+4)^(3/2)
To get a maximum value of I, we equate the derivative of I (wrt alpha) to 0, orI'(h)=0or, after a few algebraic manipulations, I'(h)=K/(h^2+4)^(3/2)-(3*h^2*K)/(h^2+4)^(5/2)=K*sqrt(h^2+4)(2h^2-4)/(h^2+4)^3We see that I'(h)=0 if 2h^2-4=0, giving h=sqrt(4/2)=sqrt(2) feet above the table.
We know that I(h) is a minimum if h=0 (flat on the table) or h=infinity (very, very far away), so instinctively h=sqrt(2) must be a maximum.Mathematically, we can derive I'(h) to get I"(h) and check that I"(sqrt(2)) is negative (for a maximum).  If you wish, you could go ahead and find that I"(h)=(sqrt(h^2+4)*(6*h^3-36*h))/(h^2+4)^4, and find that the numerator equals -83.1K which is negative (denominator is always positive).
An alternative to showing that it is a maximum is to check the value of I(h) in the vicinity of h=sqrt(2), say I(sqrt(2) +/- 0.01)we findI(sqrt(2)-0.01)=0.0962218KI(sqrt(2))     =0.0962250K   (maximum)I(sqrt(2)+0.01)=0.0962218KIt is not mathematically rigorous, but it is reassuring, without all the tedious work.
3 0
3 years ago
What is the shape of the cross-section formed when a cylinder intersects a plane as shown in the drawing?
elena55 [62]

Answer:

There is no drawing we will not be able to answer your question.

Step-by-step explanation:


8 0
4 years ago
(WILL GIVE BRAINLIEST) Describe how you would simplify the given expression.
Vinil7 [7]

Answer:

Simplify inside the parentheses by dividing coefficients, subtracting the exponents on like bases, and raising the resulting expression to the –3 power. Then, write bases with positive exponents.

Raise the numerator and denominator to the –3 power. Then, using the power of a power property, multiply the exponents. Divide the coefficients and subtract the exponents on like bases, then write with positive exponents.

Step-by-step explanation:

3 0
3 years ago
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