Okay, so
a=2b+11
<span>a+b = 2(a-b) </span>
<span>now solve </span>
<span>a+b = 2a-2b </span>
<span>3b = a, put that into the 1st equation: </span>
<span>3b = 2b+11 </span>
<span>b=11 </span>
<span>a = 2(11) +11 = 33 </span>
<span>check in the 2nd equation: </span>
<span>33+11 = 2(33-11) </span>
<span>44 = 2(22) </span>
<span>44 = 44</span>
Step-by-step explanation:
L.H.S
tanA * cosecA
=sinA/cosA * 1/sinA
now cancel sinA and sinA
then,
1/cosA
= secA
= RHS
hence proved
By using the base change formula, which states

The given equation is 
By substituting the values of log 5 and log 3.

= 1.46
Answer:
x>0
Step-by-step explanation:
i took the quiz :))