Answer:
Domain and Range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively
Step-by-step explanation:
We have the functions, f(x) = eˣ and g(x) = x+6
So, their composition will be g(f(x)).
Then, g(f(x)) = g(eˣ) = eˣ+6
Thus, g(f(x)) = eˣ+6.
Since the domain and range of f(x) = eˣ are all real numbers and positive real numbers respectively.
Moreover, the function g(f(x)) = eˣ+6 is the function f(x) translated up by 6 units.
Hence, the domain and range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively.
I think the remaining number is x
Avg. speed Joanna runs: 7.5km/h
how much she runs everyday: 15km
15km/7.5= 2 hours of running time everyday
She leaves at 8:30, comes back at ?
8:30+ 2:00= 10:30
Joanna arrives back at 10:30a.m.
Answer:
59°
Step-by-step explanation:
From the diagram, shown in the attachment line x and y are parallel lines.
Angle 7 and angle 6 are angles on a straight line.
The two angles will add up to 180 degrees.
But angle 7 measures 121°.
This implies that:
Solve for angle 6 to get;
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Answer:
More than 10% of Gillway students earned honors.
Step-by-step explanation:
<u>Step 1: Find the number of students who earned honors</u>
43 + 17 = 60
<u>Step 2: Find the total number of students</u>
381 + 108 = 489
<u>Step 3: Find the percentage of students who earned honors</u>
Students who earned honors/Total students x 100
60/489 x 100
12.27%
<u>Step 4: Find the correct answer</u>
Just under 11% of Gillway students earned honors.
<em>This is incorrect since the percentage is more than 11%.</em>
Just over 11% of Gillway students earned honors.
<em>This is incorrect as just over 11% would mean somewhere between 11 and 12% whereas the actual percentage is just over 12%.</em>
More than 10% of Gillway students earned honors.
<u><em>This is correct as compared to all other statements since 12.27% is more than 10%.</em></u>
Almost 11% of Gillway students earned honors.
<em>This is incorrect since almost 11% means less than 11% whereas the actual percentage is more than 11%.</em>
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