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aalyn [17]
3 years ago
15

Find m AEB 66.5 133 266 227

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
3 0

Answer:

The measure of arc AEB is 266\°

Step-by-step explanation:

we know that

The inscribed angle measures half that of the arc comprising

so

133\°=\frac{1}{2}(arc\ AEB)

arc\ AEB=2*133\°=266\°

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In ΔBCA, CB = 11 cm, CG = 6 cm, AH = 9 cm. Find the perimeter of ΔBCA. Triangle BCA with inscribed circle D. Segments BF and BH,
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Answer:

The perimeter of Δ ABC is 40 cm ⇒ 2nd answer

Step-by-step explanation:

* Lets explain how to solve the problem

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∴ BF = BH ⇒ tangents drawn from a point outside the circle

- CF and CG are tangents to circle D from point C

∴ CF = CG ⇒ tangents drawn from a point outside the circle

- AG and AH are tangents to circle D from point A

∴ AG = AH ⇒ tangents drawn from a point outside the circle

∵ CG = 6 cm ⇒ given

∴ CF = 6 cm

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∵ CB = CF + FB

∴ 11 = 6 + FB ⇒ subtract 6 from both sides

∴ FB = 5 cm

∵ FB = BH

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∵ AH = 9 cm ⇒ given

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∴ AB = 9 + 5 = 14 cm

∵ AC = AG + GC

∴ AC = 9 + 6 = 15 cm

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∴ The perimeter of Δ ABC = 14 + 11 + 15 = 40 cm

* The perimeter of Δ ABC is 40 cm

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Yun was trying to factor 7x^2-14x7x
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the width of Yun's area model is 7x units or ( x-2 )units .

<u>Step-by-step explanation:</u>

Here we have , Yun was trying to factor 7x^2-14x.  He found that the greatest common factor of these terms was 7x and made an area model:  What is the width of Yun's area model. Let's find out:

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