Question

For the function f(t) = Pe^rt, if P= 3 and r = 0.03 what is the value of f(3) to the nearest tenth? A: 2.5 B: 3.3 C: 7.4 D: 1.1

Answer 1

B, You plug in the numbers like 3e^(3*.03) for 3.3

Answer 2

Answer:

B. 3.3

Step-by-step explanation:

We have been given a function $f(t)=Pe^{rt}$. We are asked to find the value of f(3), when $P=3\text{ and }r=0.03$.

Upon substituting our given values our function would be $f(t)=3e^{0.03t}$.

To find f(3), we will substitute $t=3$ in our given function as:

$f(3)=3e^{0.03*3}$

$f(3)=3e^{0.09}$

$f(3)=3*1.0941742837052104$

$f(3)=3.2825228511156312$

$f(3)\approx 3.3$

Therefore, the value of $f(3)$ is approximately 3.3 and option B is the correct choice.