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4 years ago

What is the abbreviation for SI unit of mass

2 answers:

8 0

I would go with either NIST or SIKG. I put SIKG because the abbreviation for mass is kg and you r look for the SI unit of mass and then the SI stands for International System of units. So when you put both SI And KG (kilograms=mass) it makes SIKG.

This is probably not right but I tried.

Good Luck!

vovangra [49]4 years ago

4 0

Kilogram
Kg I think I did this last year sk

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The equation Y-5<br> 5(x-4) is written in point-slope form. What is the y-intercept of the equation?

nirvana33 [79]

Answer:

The y-intercept is -15.

Step-by-step explanation:

y - 5 = 5(x - 4) is our equation in point-slope form.

point slope form is = y - y1 = m( x - x1)

So, we know that the slope is 5 and one point is (4, 5)

We can use this point and the slope to find the y -intercept.

y = mx + b is slope intercept form.

Let's input the values we know to find the y-intercept.

5 = 5(4) + b

5 = 20 + b

-15 = b

The y-intercept is -15.

4 0

3 years ago

Read 2 more answers

Why is apr an important tool for consumers

My name is Ann [436]

Answer:

APR, or annual percentage rate, is your interest rate stated as a yearly rate. An APR for a loan can include fees you may be charged, like origination fees. APR is important because it can give you a good idea of how much you'll pay to take out a loan.

6 0

2 years ago

Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. (a) Descr

Daniel [21]

Answer:

(a) The sampling distribution of $\overline{X}$ = Population mean = 79

(b) P ( $\overline{X}$ greater than 81.2 ) = 0.1357

(c) P ( $\overline{X}$ less than or equals 74.4 ) = .0107

(d) P (77.6 less than $\overline{X}$ less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean $(\nu)$ = 79

Standard deviation $(\sigma )$ = 18

(a) Describe the sampling distribution of $\overline{X}$

For large sample using central limit theorem

the sampling distribution of $\overline{X}$ = Population mean = 79

(b) What is Upper P ( $\overline{X}$ greater than 81.2 ) =

$P(\overline{X}> 81.2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})$

= $P(Z> 1.1)$

= $1 - P(Z< 1.1)$

= 1 - .8643 =

= 0.1357

$P(\overline{X}\leq 74.4)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{74.4- 79}{\frac{18}{\sqrt{81}}})$

= $P(Z\leq -2.3)$

= .0107

(d) What is Upper P (77.6 less than $\overline{X}$ less than 83.2 ) =

$P(77.6< \overline{X}< 83.2)$ = $P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{83.2- 79}{\frac{18}{\sqrt{81}}})$