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Mariulka [41]
3 years ago
9

2 x (7-4)^2 - (8 x 2 + 2)/2 = (the x indicates multiply)

Mathematics
1 answer:
alexdok [17]3 years ago
5 0
2 × 3² - 18/2
2 × 9 - 9
18 - 9
= 9
hopefully this is corrrct ,^_^
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2) 0.6148.24<br> 3<br> I really need help y’all its really hard
BartSMP [9]

Answer:

0.012

Step-by-step explanation:

0.6/48.24

1. multiply numerator and denominator by 100 to get 60/4824

2. divide 60 by 4824

3. you get 0.012

( i would've written out how to get that answer but there are about 10 steps and it's really hard to type them out)

6 0
2 years ago
A right triangle has legs measuring 18 in. and 26 in.
creativ13 [48]
Do sqrt(18^2)+26^2)). It should give you the answer.

8 0
2 years ago
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Don’t know how to solve
VladimirAG [237]

Answer:

(based on the given information) -21 - 8 = 31 + 10 = 41

Step-by-step explanation:

it's like adding 3 + 1, because there is nothing to add in the ones place

7 0
2 years ago
In JKL and PQR, if JK PQ, KL QR, and K Q, then JKL must be congruent to PQR.
Pavlova-9 [17]

True!


Two shapes are congruent if when turning, flipping or sliding one shape it can become another. This problem is illustrated in the Figure below. So, you can see that we have two triangles ΔJKL and ΔPQR. As you can see:

  • JK=PQ
  • KL=QR
  • ∠K=∠Q

Given that two sides are equal to two other sides and one angle is equal to another one, then JL= PR. Accordingly, since all the sides are congruent, then the whole triangle JKL is congruent to PQR

8 0
3 years ago
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Find the equation of the line using the point-slope formula. Write the final equation using slope-intercept form. Perpendicular
polet [3.4K]

Answer:

<u>Slope-intercept form</u>: y = -5x - 8

<u>Point-slope form</u>:  y - 2 = -5(x + 2)

Step-by-step explanation:

Given the equation, 5y = x - 4, which passes through point (-2, 2):

Transform the given equation into its <u>slope-intercept form</u>, y = mx + b.

In order to do so, divide both sides by 5 to isolate y:

5y = x - 4

\displaystyle\mathsf{\frac{5y}{5}\:=\:\frac{1x\:-\:4}{5}}

\displaystyle\mathsf{y\:=\:\frac{1}{5}x\:-\:\frac{4}{5}}  ⇒  This is the slope-intercept form of 5y = x - 4.

Next, we must determine the equation of the line that is perpendicular to \displaystyle\mathsf{y\:=\:\frac{1}{5}x\:-\:\frac{4}{5}}.    

<h2>Definition of Perpendicular Lines:</h2>

<u>Perpendicular lines</u> have <em>negative reciprocal</em> slopes.  This means that if we multiply the slopes of two lines, their product will equal to -1.  

In other words, if the slope of the given equation is m₁, and the slope of the other line perpendicular to the given linear equation is m₂, then:  m₁ × m₂ = -1.

  • Slope of the given equation: m₁ = ⅕
  • \displaystyle\mathsf{Slope\:of\:other\:line\:(m_2 )\:=\:-5\:or\:-\frac{5}{1}}

If we multiply these two slopes:

  • m₁ × m₂ = -1
  • \displaystyle\mathsf{m_1\:\times\\\:m_2\:=\:\frac{1}{5}\times\\-\frac{5}{1}\:=\:-1}

Now that we have identified the slope of the other line that is perpendicular to  5y = x - 4, we must determine the y-intercept of the <u>other line</u>.  

  • The <u>y-intercept</u> is the point on the graph where it crosses the y-axis, for which it is the value of "y" when its corresponding x-coordinate equals to zero (0).
  • Thus, the standard coordinates of the y-intercept is (0, <em>b</em>), for which its y-coordinate is the value of "<em>b</em>" in the slope-intercept form, y = mx + b.

Using the <u>slope</u> of the other line, m₂ = -5, and the given point, (-2, 2), substitute these values into the slope-intercept form to find the value of the y-intercept, <em>b</em>:

y = mx + b

2 = -5(-2) + b

2 = 10 + b

Subtract 10 from both sides to isolate b:

2 - 10 = 10 - 10 + b

-8 = b

The equation of the other line that is perpendicular to 5y = x - 4 is:

Linear Equation that is perpendicular to 5y = x - 4 in slope-intercept form:  

<h3>⇒   y = -5x - 8 </h3>

<h2>Rewrite the Equation in Point-slope Form:</h2>

The <u>point-slope form</u> is: y - y₁ = m(x - x₁)

In order to rewrite y = -5x - 8 in its point-slope form, we must substitute the value of the given point, (-2, 2) into the point-slope form:

y - y₁ = m(x - x₁)

y - 2 = -5[x - (-2)]

y - 2 = -5(x + 2) ⇒  This is the <u>point-slope form</u> of the line that is perpendicular to 5y = x - 4.

6 0
2 years ago
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