Answer:
74
Step-by-step explanation:
Say that arc JL going through M is arc E and JL going the other way is arc D
For the angle formed by two tangents, K=(1/2)(E-D)
64=E-D
Furthermore, angle K and central angle JCL (facing toward K) are supplementary, so 180-K=JCL=180-32=148
Thus, as the angles around angle C add up to 360, angle JCL (facing toward M) is 360-148=32+180=212
E is then 212
64=212-D
212-64=D=148
Thus, as JML is an inscribed angle, M=1/2(D)=1/2(148)=74
First find the length of the longest leg
x^2 = 13^2 - 5^2 ( by the Pythagoras theorem)
x^2 = 144
x = 12
Area of the traingle = 1/2 * base * height
= 1/2 * 5 * 12
= 30 units^2
Answer: Quadrant 1 and 3
Step-by-step explanation:
Substitute the f(x) and g(x) following the required operations:
A. (f+g)x = (x^2 + 1) + (x + 1) = x^2 + x + 2
B. (f-g)x = (x^2 + 1) - (x + 1) = x^2 - x
C. (fg)x = (x^2 + 1)(x + 1) = x^3 + x^2 + x + 1
D. (f/g)x = (x^2 + 1) / (x + 1) or x - 1 + 2/(x+1) if answer must be in expanded form
E. (f o g)x = (x+1)^2 + 1 = x^2 + 2x + 2
F. (g o f)x = (x^2 + 1) + 1 = x^2 + 2