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3 years ago

Find the real number root. sqrt-2.56

Mathematics

2 answers:

VARVARA [1.3K]3 years ago

3 0

Simplify the radical by breaking down the radicand up into a product of known factors.
1.6i

iVinArrow [24]3 years ago

3 0

The answer to your question is "No real number root"

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Wave Corporation began the current year with a retained earnings balance of $25,000. During the year, the company corrected an e

Hitman42 [59]

Answer:

$30,000.

Step-by-step explanation:

Wave Corporation began the current year with a retained earnings balance of $25,000.

Depreciation expense was of $5000

During the current year, the company earned net income of $15,000

Also gave cash dividends of $5,000.

So, year end retained earnings will be :

Year end retained balance = total net income minus net losses and dividends.

$25000-5000+15000-5000=30000$ dollars

The answer is $30,000.

7 0

2 years ago

Given f(x) = 4x^2 + 19x - 5 and g(x) = 4x^2 - x what is (f/g)(x)?

Free_Kalibri [48]

$( \frac{f}{g} )(x) = \frac{4 {x}^{2} + 19x - 5}{4 {x}^{2} - x} = \frac{(4x - 1)(x + 5)}{x(4x - 1)} = \frac{x + 5}{x}$

3 0

2 years ago

Read 2 more answers

Question (Multiple Choice Wor (07.01) Which of the values in the set {3,4,5,6) is a solution to the equation 4x + 2 = 22? 3 4 5

Murljashka [212]

Answer:

4x+2=22

4x+2-2=22-2

4x=20

4x/4=20/4

x=5

6 0

3 years ago

Mohamed and Li Jing were asked to find an explicit formula for the sequence -5, -25, -125, -625,....

Nuetrik [128]

Answer:

Li Jing's formula i.e. $\boxed{g_n=-5\cdot \:5^{n-1}}$ is right.

Step-by-step explanation:

Considering the sequence

$-5,\:-25,\:-125,\:-625,...$

A geometric sequence has a constant ratio r and is defined by

$g_n=g_0\cdot r^{n-1}$

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{g_{n+1}}{g_n}$

$\frac{-25}{-5}=5,\:\quad \frac{-125}{-25}=5,\:\quad \frac{-625}{-125}=5$

$\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}$

$r=5$

So, the sequence is geometric.

$\mathrm{The\:first\:element\:of\:the\:sequence\:is}$

$g_1=-5$

$r=5$

$g_n=g_1\cdot r^{n-1}$

$\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:$

$g_n=-5\cdot \:5^{n-1}$

Therefore, Li Jing's formula i.e. $\boxed{g_n=-5\cdot \:5^{n-1}}$ is right.

8 0

3 years ago

Find the values for c and d

baherus [9]

Answer:

c=-5

d=1

Step-by-step explanation:

$(cy^2)(4y^d)=-20y^3$

I'm going to reorder the left-hand side. Multiplication is commutative.

$(4c)(y^2y^d)=-20y^3$

Since the bases are the same in $y^2y^d$ and the operation is multiplication, I'm going to add the exponents giving me:

$4cy^{2+d}=-20y^3$

So this implies we have two equations to solve:

$4c=-20$ and $2+d=3$

So the first equation can be solved by dividing both sides by 4 giving you $c=-5$ .

The second equation can be solved by subtracting 2 on both sides giving you $d=1$ .

6 0

3 years ago