Rewrite <span>2cos x + 1 = 0 as:
2 cos x = -1, and then cos x = -1/2
x must be in Quadrant II or Quadrant III, since the adj. side is negative.
Note that the angle 120 has adj. side -1 and hyp 2. So 120 degrees is one solution.
Now what about a possible 2nd solution, to be found in Quadrant III? That would be -120 degrees, which has the same terminal line as does 240 degrees.
No soap.
So, the solution is 120 degrees.</span>
Answer:
Step-by-step explanation:
1) ?
I can't see what that one given angle is .. but it's that mystery angle subtracted from 180 give the angle BOA then you know that's an isosceles triangle again that the BOA is part of... so then just subtract BOA from 180 to find the two other angle of that triangle... they are the small so just divide your answer of 180-BOA /2 is the angle of each.. then since you know those to smaller angles subtract one from 90 to find the angle BAX
2) ( as we would read normally)
You're making this really tough on me.. I can just barely read the equations
I think it's 1+6x and 7x-3 . b/c they are the same length sides you can set those equal
1+6x = 7x -3
4+6x = 7x
4 = x
that worked out well :
for the tangent.. it's Tan(Ф)= Opp/ Adj
but I don't know which side they want to solve for.. I think you may have left off some of the instructions???? :/
ohh I think they really mean.. what's the length of the tangent lines .. that was confusing to me.. :/ just plug in 4 into x for either eq.
1+6(4) = 25
or
7(4)-3=25
tangent is 25
3)
x-2 = 2x-10
x+8 = 2x
8 = x
again they made it work out easy :)
Then plug 8 into either equation to find the length of the tangent lines
8-2=10
tangent is 10
4) = 2) ??? they are the same question maybe you meant to put something else?
Answer:
A
Step-by-step explanation:
1.020 is less than 1.200
Answer:
m∠C = 122°
Step-by-step explanation:
Opposite angles of a quadrilateral inscribed in a circle are supplementary. This means
m∠A + m∠C = 180°
m∠B + m∠D = 180°
To find angle C we need to find x, then subtract m∠A from 180°
x+20=3x
20=2x
x=10
Now we substitute 10 in for x
m∠A=2(10)+38
m∠A=20+38
m∠A=58°
Now we subtract this value from 180.
m∠C=180-58
m∠C=122°
