The answer is Tailoring the baseline to their needs.
After an organization selects applicable security control baseline but finds not all of the controls apply, it initiates a tailoring process to modify the controls appropriately and more closely with specific conditions related to organizational missions, information systems or environments of operation. It is an integral part of the security control selection and specification and involves risk management processes like assessing, responding to, and framing.
Answer: 545 words per 35 mins
Explanation:
Here is a somewhat cryptic solution that works:
#include <algorithm>
#include <cstdlib>
using namespace std;
void q(char c, int count)
{
for (int i = 0; i < count; i++) {
putchar(c);
}
}
void p(int b1, int plusses)
{
q(' ', b1);
q('+', plusses);
}
int main()
{
for (int i = -3; i <= 3; i++)
{
int pl = min(6, (3 - abs(i)) * 2 + 1);
p(6-pl, pl);
i == 0 ? p(0, 6) : p(6, 0);
p(0, pl);
putchar('\n');
}
getchar();
}
Answer:
ENIAC, UNIVAC, EDVAC and IMB 1401 are the list of computers used in history of computer
Explanation:
hope it helps
plz make it brainliest ans
Answer:
0.8488
Explanation:
Let E =error found by test 1
Let F=error found by test 2
Let G=error found by test 3
Let H=error found by test 4
Let I= error found by test 5
Given P(E)=0.1, P(F)=0.2, P(G)=0.3, P (H)= 0.4, P (I)=0.5
therefore P(notE)=0.9, P(notF)=0.8, P(notG)=0.7, P(not H)=0.6, P (notI)=0.5
Tests are independent P(not E & not F ¬ G & not H & not I=P(notE)*P(notF)*P(notG)*P (notH)*P (not I) =0.9*0.8*0.7*0.6*0.5 =0.1512
P(found by at least one test)= 1- P(not found by any test)=1-P(not E& not F & not G & not H & not I ) = 1-0.1512 = 0.8488
