Answer:
From DRAM to DDR4
Explanation:
RAM stands for <em>Random Access Memory.</em> In 1968, Mr. Robert Dennard at IBM's Watson Research obtained the patent for the one-transistor cell that will eventually substitute the old magnetic core memory allocated in computers of the time. By 1969 Intel released the TTL bipolar 64-bit SRAM (Static Random-Access Memory) as well as the ROM "Read Only Memory"; also in 1969 it evolved into "<em>Phase - change memory - PRAM - </em>". However this evolution was not commercialized, Samsung expressed its interest in developing it. In 1970 the first DRAM product was commercially available; it was developed by Intel. In 1971 it was patented EPROM; in 1978 George Perlegos developed EEPROM.
By 1983 a nice breakthrough happened with the invention of SIMM by Wang Labs. In 1993 Samsung came up with KM48SL2000 synchronous DRAM (SDRAM), this variation soon turned into an inductry standard.
In 1996 DDR began a revolution in the memory sector, then in 1999 RDRAM. Both DDR2 SDRAM. DDRR3 and XDR DRAM were commercialized. Finally in 2007 and 2014 the developments of DDR3 and DDR4 were available for the general public.
Answer:
The output is 24
Explanation:
Given
The above code segment
Required
The output
We have (on the first line):
On the second line:
Substitute the value of each variable
Solve the inner brackets
8%3 implies that, the remainder when 8 is divided by 3.
The remainder is 2
So:
<em>Hence, the output is 24</em>
Answer:
Option A i.e., SME for further investigation.
Explanation:
Following the reports of such a security incident into an SOC, an incident respondent examines the incident but could not determine the cause of that same incident as well as establish an appropriate response protocol. The ticket for an incident must be applied to SME for even more inquiry. So, the following answer is correct.
It depends on a language you code. I think this could be either C++ or Java. I know answer for both of them.
For C++: <span>address.find("Avenue")
For Java: </span><span>address.indexOf("Avenue")</span>
Answer:
I have no clue. I wish I could help though.
Explanation:
Sorry
