An equation that is true for all values of the variables in its domain is <u>an identity</u>
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Answer:
4 it wll have to be my friend
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the consecutive even numbers be 2n , (2n + 2) , (2n +4), (2n + 6)
2n + 2n+2 + 2n+4 + 2n+6 = 180
Add like terms
<u>2n + 2n + 2n + 2n</u> + <u>2 + 4 + 6</u> = 180
8n + 12 = 180
Subtract 12 from both sides
8n + 12 - 12 = 180 - 12
8n = 168
Divide both sides by 8
8n/8 = 168/8
n = 21
2n = 2*21 = 42
2n + 2= 2*21 +2 = 42 +2 = 44
2n +4 = 2*21 + 4 = 42 + 4 = 46
2n +6 = 2*21 + 6 = 42 + 6 = 48
The 4 consecutive even integers: 42, 44 , 46 , 48
Answer:
y=1/6x+13/3
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(5-4)/(4-(-2))
m=1/(4+2)
m=1/6
y-y1=m(x-x1)
y-4=1/6(x-(-2))
y-4=1/6(x+2)
y=1/6x+2/6+4
y=1/6x+1/3+4
y=1/6x+1/3+12/3
y=1/6x+13/3