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3 years ago

10

each bag of pattern blocks contains 50 block. to make a class pattern, the teacher combines 4 bags of blocks. how many pattern b

locks are there?

1 answer:

Elodia [21]3 years ago

8 0

50(4)= 200

There are 200 pattern blocks.

Hope this helps!

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Solve the following proportion by cross multiplying:<br> ( x - 3 ) / 4 = ( 2x + 2 ) / 6

vichka [17]

Answer:

- 13

Step-by-step explanation:

Solving

$\frac{(x - 3)}{4} = \frac{(2x + 2)}{6} \\ \\ cross \: multiplying \\ 6 \times (x - 3) = 4 \times (2x + 2) \\ 6x - 18 = 8x + 8 \\ 6x - 8x = 8 + 18 \\ - 2x = 26 \\ dividing \: bothsides \: by \: - 2 \\ \frac{ - 2x}{ - 2} = \frac{26}{ - 2} \\ x = - 13$

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2 years ago

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What is the y-intercept of the line?

Akimi4 [234]

Answer:

a. 11

Step-by-step explanation:

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3 years ago

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An acre measures 4840 square yards. In a city, a lot on which a single-

belka [17]

The lot is <u>9.2% of the an acre.</u>

<u>Given:</u>

Area of an acre = 4840 sq. yards

Area of lot = 40 by 100 ft = $40 ]\times 100 = 4,000 $ ft^{2}$

Convert the area of the lot to feet ( $9 ft^{2} = yd^{2}$ ):

<em>Therefore:</em>

Area of lot = $\frac{4,000}{9} = 444.4 $ yd^{2}$

Percentage occupied by the lot = area of lot / area of acre x 100

$= \frac{444.4}{4840} \times 100\\\= 9.2$

The lot therefore is <u>9.2% of the an acre</u>.

Learn more here:

brainly.com/question/20730855

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2 years ago

The minimum value of Y in the equation y = x2 - 6x + 8

murzikaleks [220]

Given

$y=x^2-6x+8$

To obtain the minimum value of y, we first take the derivative of y

The derivative of y is:

$y^{\prime}=2x-6$

Equating

$y^{\prime}\text{ = 0}$

gives the minimum value we require.

Doing that, we have:

$2x-6=0$

So that

$\begin{gathered} 2x=6 \\ x=\frac{6}{2} \\ =3 \end{gathered}$

Therefore, the minimum value is x = 3

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1 year ago

What are the x-intercepts of the graph of the quadratic function

Svetllana [295]

Zero Product Property: if a × b = 0, then either a or b = 0 or both a and b = 0.

(Make sure to set f(x) to zero)

So for this equation, I will be factoring by grouping. Firstly, what two terms have a product of -5x^2 and a sum of 4x? That would be 5x and -x. Replace 4x with 5x - x: $0=5x^2+5x-x-1$

Next, factor 5x^2 + 5x and -x - 1 separately. Make sure that they have the same quantity on the inside: $0=5x(x+1)-1(x+1)$

Now you can rewrite the equation as: $0=(5x-1)(x+1)$

Now apply zero product property to the factors to solve for x:

$5x-1=0\\5x=1\\x=\frac{1}{5}\\\\x+1=0\\x=-1$

<u>The x-intercepts are (1/5 ,0) and (-1,0).</u>

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3 years ago