Answer:
Part 1) The exponential function is equal to 
Part 2) The population in 2010 was 
Step-by-step explanation:
Part 1) Write an exponential decay function that models this situation
we know that
In this problem we have a exponential function of the form
where
y ----> the fish population of Lake Collins since 2004
x ----> the time in years
a is the initial value
b is the base
we have
substitute
----> exponential function that represent this scenario
Part 2) Find the population in 2010
we have
so
For 
substitute
Sounds like you’re missing a piece in this problem
Step 1: 654.75-15.00= $639.75
Therefore the club made $639.75
1) slope = (y₂-y₁)/(x₂-x₁)
Let A and B be A(4,-6) and B(0,2) ;
m = [2-(-6)]/[0-4) = (2+6)/(-4) → m = -2
2) Midpoint = value of x of the midpoint = (x₁+x₂)/2
value of y of the midpoint = (y₁+y₂)/2
x(midpoint) = (4+0)/2 → x= 2
y(midpoint) = (-6+2)/2 → y= - 2, so Midpoint M(2,-2)
3) Slope of the perpendicular bisector to AB:
The slope of AB = m = -2
Any perpendicular to AB will have a slope m' so that m*m' = -1 (or in other term, the slope of one is inverse reciprocal of the second, then if m =-2, then m' = +1/2 ; Proof [ (-2)(1/2) = -1]
4) Note that the perpendicular bisector of AB passes through the midpoint of AB or M(2,-2). Moreover we know that the slope of the bisector is m'= 1/2
The equation of the linear function is :
y = m'x + b or y = (1/2)x + b. To calculate b, replace x and y by their respective values [in M(-2,2)]
2= (1/2).(-2) + b → 2 = -1 + b → and b= 3, hence the equation is:
y = (1/2)x + 3
<h3>Step-by-step explan:</h3><h3><u>45</u></h3><h3><u>decenas </u></h3>
