2) 48
3) 72
4) 48
5) 105
6) 47
7) 37
8) 400
9) 17
10) 13
I hope this helps! Let me know if I get anything wrong so I can fix it.
Answer:
the height of the porch is H=1.91 m
Step-by-step explanation:
neglecting friction and assuming that the porch is horizontal, then the horizontal speed is v₀= 4 m/s and it does not change , thus he hits the base at
t= L/v₀ , L= horizontal distance
then for vertical motion , since the vertical velocity vy is 0 , the initial height is H ( the height of the porche) and the final height hf is 0 , we have
hf = H + vy*t - 1/2*g*t²
0 = H + 0 -1/2*g*t²
H = 1/2*g*t² = 1/2*g*(L/v₀)²
replacing values with g= gravity = 9.8 m/s²
H = 1/2*g*(L/v₀)² = 1/2*9.8 m/s² *( 2.5 m/ 4 m/s)² = 1.91 m
therefore the height of the porch is H=1.91 m
Where is the picture at?? I can’t help you
Take the derivitive
f'(x)=3x^2+12x
find where it equals zero
it equal zero at x=0 and x=-4
find the y values
f(0)=-36
f(-4)=-4
the critical points are (0,-36) and (-4,-4)
make sign chart
evalutat f'(x) at x=-5 and x=-1 and x=1, and see their signs
f'(-5)=(+)
f'(-1)=(-)
f'(1)=(+)
see below attachment
max is where sign changes from (+) to (-)
min is where sign changes from (-) to (+)
so
max at (-4,-4)
min at (0,-36)
none of the options are correct, do you have te right problem?