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3 years ago

15

The Greasy Grab Bag claims that customers can make 20 different meal combinations from the menu items. If the Greasy Grab Bag ha

s 4 sandwiches, 3 sides, and 2 drinks, which of the following is correct?

1 answer:

RUDIKE [14]3 years ago

6 0

The answer is A. <span>The Greasy Grab Bag is understating the number of meal combinations.</span>
4 * 3 * 2 = 24
and 24 > 20

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Find the equation of the line that is perpendicular to y = - 1/3 x + 2 and passes though the point (-5,2)

elena55 [62]

Answer:

y - 2 = 3(x + 5)

Step-by-step explanation:

The given equation has slope -1/3. Any line perpendicular to the given line has a slope which is the negative reciprocal of -1/3, which comes out to +3.

Use the point-slope formula y - k = m(x - h):

y - 2 = 3(x + 5)

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3 years ago

Convert each rational number into its decimal form. 1. 1/3 2. 1/6 3. 1/9

stepladder [879]

Answer:

1. 0.33 2. 0.16 3. o.11

Step-by-step explanation:

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2 years ago

Sarkis wants to draw a triangle with sides measuring 4 ft, 10 ft, and 16 ft. Which is true about Sarkis’s plan?

Liono4ka [1.6K]

Answer:

Sarkis cannot draw a triangle with these side lengths.

Step-by-step explanation:

Sarkis cannot draw a triangle with these side lengths.

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2 years ago

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

3 years ago

The ratio 25:45 in simplest form is

stepladder [879]

25/45=(5∗5)/(5∗9)=5/9

5/9 is the answer.

5 0

3 years ago

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