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Archy [21]
2 years ago
10

What is the equation of the line that is parallel to the line 3x+4y=2 and passes through the point (4.-1)

Mathematics
1 answer:
geniusboy [140]2 years ago
6 0

Step-by-step explanation:

The eqn is

3x+4y=2

slope=-xcoeff/ycoeff

m=-3/4

the eqn is

y-y1=m(x-x1)

y+1=-3/4(x-4)

4y+4=-3x+12

3x+4y=8

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-4(-3n-8)=104<br> A:11<br> B:-6<br> C:10<br> D:6
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♡ The Question ♡

-  -4(-3n-8)=104

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ The Answer ♡

-  D) 6

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ The Explanation/Step-By-Step ♡

-  -4(-3n - 8) = 104

Divide both sides by -4!

-4(-3n - 8) over -4 = 104/-4

Simplify!

-3n - 8 = -26

Add 8 to both sides!

-3n - 8 + 8 = -26 + 8

Simplify!

-3n = -18

Divide both sides by -3!

-3n/-3 = -18/-3

Simplify!

n = 6

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ Tips ♡

- No tips provided!

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