I don't know if there are any options....so I did reasearch I found the question and I believe it is graph 4 because it intersects at (1,5)!
A=1x3 means 1 row and 3 columns.
B=3x4 means 3 rows and 4 columns.
AB is a compatible multiplication because A has three columns and B has 3 rows.
However, BA is not a compatible multiplication because B has 4 columns while A has only 1 row.
The general trick is if you read the row/column of the two matrices as 1-3-3-4, and the two middle ones are identical, then AB would be a compatible multiplication. On the other hand, BA would read 3-4-1-3, since 4 and 1 are not identical, so it is not a valid multiplication.
Do remember 1x3 means 1 ROW and 3 COLUMNS.
Answer:
a = l +6
Step-by-step explanation:
andrew = lauren + 6
<h3>Given</h3>
- a rectangle x units wide and y units high divided into unit squares
<h3>Find</h3>
- The total perimeter of the unit squares, counting each line segment once
<h3>Solution</h3>
For each of the y rows of squares, there are x segments at the top, plus another x segments at the bottom. The total number of horizontal segments is then
... horizontal segment count = (y +1)x
Likewise, for each of the x columns of squares, there are y segments to the left, plus another y segments to the right of the entire area. Then the total number of vertical segments is
... vertical segment count = (x+1)y
The total segment count is ...
... total segments = horizontal segments + vertical segments
.. = (y+1)x +(x+1)y
... total segments = 2xy +x +y
_____
<u>Check</u>
We know a square (1×1) has 4 segments surrounding it.
... count = 2·1·1 +1 +1 = 4 . . . . (correct)
We know the 3×3 window in the problem statement has 24 segments.
... count = 2·3·3 +3 +3 = 18 +3 + 3 = 24 . . . . (correct)
We know a 1×3 row of panes will have 10 frame elements.
... count = 2·1·3 +1 +3 = 6 +1 +3 = 10
It looks like our formula works well.
