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3 years ago

Rent-Me Rent-A-Car charges $25.00 per day plus $0.14 per mile to rent an 1 point

Mathematics

1 answer:

Sliva [168]3 years ago

6 0

Answer:

50 miles

Step-by-step explanation:

Let the number of miles driven by each car by represented by x

Rent-Me Rent-A-Car charges $25.00 per day plus $0.14 per mile to rent an economy car.

Hence,

$25.00 + $0.14x .......Equation 1

Better Deal Rental Car charges $23.00 per day plus $0.18 per mile for the same type of car

Hence,

$23.00 + $0.18x...Equation 2

To calculate how many miles will a car rented from either company cost the same amount, we Equate both equations together

Equation 1 = Equation 2

$25.00 + $0.14x = $23.00 + $0.18x

Collect like terms

$25.00 - $23.00 = $0.18x - $0.14x

$2.00 = $0.04x

Divide both sides by $0.04

x = $2.00/$0.04

x = 50 miles

Therefore, a car rented from either company cost the same amount for 50 miles

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rebecca purchased a total of 17 books and toys for the woodbine play school. each book cost 6 dollars and each toy costs 11 doll

DochEvi [55]

Let x= the number of books purchased: 7 books purchased
let y = the number of toys purchased;10 toys purchased
Equations: x+y=17
6x+11y=152 x+10=17
-6(x+y=17) y=10 -10 -10
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-6x-6y=-102 x=7
6x+11y=152
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3 years ago

What is the scale factor of triangle ABC to DEF ?

bekas [8.4K]

Answer: The correct option is (A). 3.

Step-by-step explanation: We are given to find the scale factor of dilation from ΔABC to ΔDEF.

As shown in the figure, the lengths of the sides of ΔABC to ΔDEF are

AB = 5 units, BC = 4 units, CA = 3 units,

DE = 15 units, EF = 12 units, FD = 9 units.

We know that the scale factor is given by

$S=\dfrac{\textup{length of a side of the dilated figure}}{\textup{length of the corresponding side of the original figure}}.$

Therefore, the scale factor of dilation from from ΔABC to ΔDEF is

$S=\dfrac{DE}{AB}=\dfrac{15}{5}=3.$

Thus, the required scale factor is 3.

Option (A) is correct.

8 0

3 years ago

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I Need to find the Function Operations

Alinara [238K]

Answer:

1) $(f+g)(x)=2x^2+3x-6$

2) $(f-g)(x)=2x^2+x$

3) $(f \cdot g)(x)=2x^3-4x^2-9x+9$

Step-by-step explanation:

So we have the two functions:

$f(x)=2x^2+2x-3\text{ and } g(x)=x-3$

And we want to find (f+g)(x), (f-g)(x), and (f*g)(x).

(f+g)(x) is the same to f(x)+g(x). Substitute:

$(f+g)(x)=f(x)+g(x)\\=(2x^2+2x-3)+(x-3)$

Combine like terms:

$=(2x^2)+(2x+x)+(-3-3)$

Add:

$=2x^2+3x-6$

So:

$(f+g)(x)=2x^2+3x-6$

(f-g)(x) is the same to f(x)-g(x). So:

$(f-g)(x)=f(x)-g(x)\\=(2x^2+2x-3)-(x-3)$

Distribute:

$=(2x^2+2x-3)+(-x+3)$

Combine like terms:

$=(2x^2)+(2x-x)+(-3+3)$

Simplify:

$=2x^2+x$

So:

$(f-g)(x)=2x^2+x$

(f*g)(x) is the same to f(x)*g(x). Thus:

$(f\cdot g)(x)=f(x)\cdot g(x)\\=(2x^2+2x-3)(x-3)$

Distribute:

$=(2x^2+2x-3)(x)+(2x^2+2x-3)(-3)$

Distribute:

$=(2x^3+2x^2-3x)+(-6x^2-6x+9)$

Combine like terms:

$=(2x^3)+(2x^2-6x^2)+(-3x-6x)+(9)$

Simplify:

$=2x^3-4x^2-9x+9$

So:

$(f \cdot g)(x)=2x^3-4x^2-9x+9$

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3 years ago

A basketball team played six games. In those games, the team won by 8 points, lost by 7 , won by 9 , won by 11 , lost by 3

BigorU [14]

Answer:

Step-by-step explanation:

From the question, we were told that a basket ball team six games and in those games, the team won by 8 points, lost by 7, won 9 , won 11 , lost by 3 and won by 6

The mean difference in games scored over the six games would be calculated as the addition of the scores divided by 6

= [8 + (-7) + 9 + 11 + (-3) + 6] / 6

= 24 / 6

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3 years ago

A tree has a shadow length of approximately 9 feet. The distance from the tip of the tree to the tip of the shadow is bout 15 fe

worty [1.4K]

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3 years ago

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