Find two rational numbers between -1,36 and -1,35

BartSMP [9]

9.83
Explanation: 6+8+10+10+12+13 = 59
There are 6 numbers so 59 divided by 6 is equal to 9.833… simplified it would be 9.83

8 0

2 years ago

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The null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed

NNADVOKAT [17]

Correct clear question is;

The null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed. What parameter is being tested? H_0: μ = 5 H_1: μ ≠ 5

Is the hypothesis test left-tailed, right tailed, or two tailed? A Left tailed B Right tailed C Two tailed

What parameter is being used? A population proportion B population mean C standard deviation

Answer:

A) C - Two tailed hypothesis

B) B - Population mean

Step-by-step explanation:

We are given the hypotheses to be;. Null Hypothesis; H_0: μ = 5

Alternative hypothesis; H_1: μ ≠ 5

From the alternative hypothesis, we can see that the critical area of distribution of the parameter being tested could either be less than 5 or greater than 5 due to the not equal to sign. This means it could either be left tailed or right tailed. Thus, it is a two tailed hypothesis.

From the hypothesis, we see that the symbol μ is being used.

In statistics, μ is generally used as a symbol to denote population mean.

Thus, parameter being used/tested is population mean

4 0

2 years ago

Please help! The question is in the image

Goshia [24]

Answer:

I am pretty sure that your answer would be 3.

Step-by-step explanation:

The reason why is because if B if half of line segment AD and AD is equal to 12, then B must be equal to 6 since half of 12 is 6. Next, since C is the mid-point for line segment BD then C must be 3 since half of 6 is 3. And finally, that means line segment BC is three since it is 1/2 of BD.

Hope this helps! :)

3 0

2 years ago

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The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated b

storchak [24]

Answer:

A task time of 177.125s qualify individuals for such training.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so $\mu = 145, \sigma = 25$ .