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IRISSAK [1]
3 years ago
14

Find the value of y that makes the equation y = -x + 5 true, when x = -4.

Mathematics
2 answers:
bogdanovich [222]3 years ago
4 0
The answer is c,i believe
KengaRu [80]3 years ago
4 0
Answer is C because  -4+5=1
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27. The square of a number is 8 more than 420 minus 347. What is the<br>number?​
Stells [14]

Answer:

x=9 or -9

Step-by-step explanation:

the equation is:x^2-8=420-347

420-347=73

if x=9 then 81-8=73

and then 73=73

so x=9

hope this helps!

please mark my answer as brainliest! thanks! :)

8 0
3 years ago
Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail inste
Vladimir [108]

Answer:

The value of t test statistics is 5.9028.

We conclude that the true mean is greater than 10 at the .01 level of significance.

Step-by-step explanation:

We are given that a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail instead.

The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample mean of 14.44 with a standard deviation of 4.45 pages.

<em />

<em>Let </em>\mu<em> = true mean transmission of pages.</em>

So, Null Hypothesis, H_0 : \mu \leq 10 pages     {means that the true mean is smaller than or equal to 10}

Alternate Hypothesis, H_A : \mu > 10 pages     {means that the true mean is greater than 10}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = 14.44 pages

            s = sample standard deviation = 4.45 pages

            n = sample of fax transmissions = 35

So, <u><em>test statistics</em></u>  =  \frac{14.44-10}{\frac{4.45}{\sqrt{35} } }  ~ t_3_4  

                               =  5.9028

(a) The value of t test statistics is 5.9028.

Now, at 0.01 significance level the z table gives critical values of 2.441 at 34 degree of freedom for right-tailed test.

<em>Since our test statistics is more than the critical values of z as 5.9028 > 2.441, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis.</u></em>

Therefore, we conclude that the true mean is greater than 10.

(b) Now, P-value of the test statistics is given by the following formula;

               P-value = P( t_3_4 > 5.9028) = Less than 0.05%    {using t table)

7 0
3 years ago
Find the missing side length
Slav-nsk [51]

Answer:

x ≈ 4.8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Trigonometry</u>

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] cos∅ = adjacent over hypotenuse

Step-by-step explanation:

<u>Step 1: Identify Variables</u>

Angle measure = 58°

Adjacent side of angle = <em>x</em>

Hypotenuse = 9

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [cosine]:                    cos58° = x/9
  2. Isolate <em>x</em>:                                     9cos58° = x
  3. Evaluate:                                     4.76927 = x
  4. Rewrite:                                      x = 4.76927
  5. Round:                                        x ≈ 4.8
5 0
3 years ago
Read 2 more answers
PLEASE HELP
Svet_ta [14]

Answer:

the answer is 5.1 killograms

Step-by-step explanation:

hope this helps

8 0
2 years ago
Discuss decline or growth of population of the settlement​
statuscvo [17]

Answer:

THE INCREASE AND DECLINE OF POPULATION

Step-by-step explanation:

Up until the beginning of the industrial revolution, global population grew very slowly. ... After about 1800 the growth rate accelerated to a peak of 2.1% annually in 1968; but since then, due to the world-wide collapse of the total fertility rate, it has declined to 1.1% today (2020).

5 0
3 years ago
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