A town has a population of 5000 and grows at 4% every year. What will be the population after 7 years, to the nearest whole numb
er?
2 answers:
I think this is.. ↓
grows 4% at every year
after 7 years ↓↓
4 × 7 = 28
A town has a population of 5000
28% of 5000 = 1400
5000 + 1400 = 6400
after 7 years, town has 6400 population = after 7 year grows 28%
Answer:
This is the actual steps and answer.
Step-by-step explanation:
\text{Exponential Functions:}
Exponential Functions:
y=ab^x
y=ab
x
a=\text{starting value = }5000
a=starting value = 5000
r=\text{rate = }4\% = 0.04
r=rate = 4%=0.04
\text{Exponential Growth:}
Exponential Growth:
b=1+r=1+0.04=1.04
b=1+r=1+0.04=1.04
\text{Write Exponential Function:}
Write Exponential Function:
y=5000(1.04)^x
y=5000(1.04)
x
Put it all together
\text{Plug in time for x:}
Plug in time for x:
y=5000(1.04)^{7}
y=5000(1.04)
7
y= 6579.6589
y=6579.6589
Evaluate
y\approx 6580
y≈6580
round
You might be interested in
Answer:
1500000 cubic centimeters
The range is: 35-60
The IQR is: 11
This value is the first 25%
IQR= interquartile range
Hope this helps ;)
Answer:
2h + 15
Step-by-step explanation:
-4h + 22 + 6h -7
2h + 22 - 7
2h + 15
If you would like to solve 36 - 0.0048, you can calculate this using the following step:
36 - 0.0048 = 35.9952
The correct result would be A. 35.9952.
Answer:
It is 35x+20
Step-by-step explanation: