Answer:
i suck at math
Step-by-step explanation:
Volume is a three-dimensional scalar quantity. The depth of the YMCA lap pool is 2 meters.
<h3>What is volume?</h3>
A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
Given that the following details about the YMCA lap pool:
- The volume of the pool = 1472m³
- The length of the pool = 36.8m
- The width of the pool = 20 m
Since the pool is in the space of a right rectangular prism, therefore, the volume of the prism will be the product of length, width and depth. Therefore, the volume of the pool can be written as,
The volume of the pool = Length × width × depth
1472m³ = 36.8m × 20 m × depth of the pool
Depth of the pool = (1472m³ ) / (36.8m × 20m)
= 2 meter
Hence, the depth of the YMCA lap pool is 2 meters.
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Answer:
7.5
Step-by-step explanation:
To solve this expression, we can use PEMDAS or order of operations.
<u>Parenthesis</u>
<u>Exponents</u>
<u>Multiplication>Division (Depends on which comes first from left to right)</u>
<u>Addition>Subtraction (See Multiplication>Division)</u>
So First, lets solve the <u>Parenthesis</u>. -2/5=-.4
So now, our equation is -3/-.4
There is no exponents or multiplication, so lets just <u>Divide</u>.
-3/-.4=7.5
The solution is 7.5
Hope this helps!
Answer
Zara gets $5.50
Step-by-step explanation:
<u><em>Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.</em></u>
Answer:
Any value other than the values 
will not be a solution of 
.
Step-by-step explanation:
Considering the equation
Steps to solve the equation
As
![\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}](https://tex.z-dn.net/?f=%5Cmathrm%7BFor%5C%3A%7Dx%5E3%3Df%5Cleft%28a%5Cright%29%5Cmathrm%7B%5C%3Athe%5C%3Asolutions%5C%3Aare%5C%3A%7Dx%3D%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%2C%5C%3A%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%5Cfrac%7B-1-%5Csqrt%7B3%7Di%7D%7B2%7D%2C%5C%3A%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%5Cfrac%7B-1%2B%5Csqrt%7B3%7Di%7D%7B2%7D)
![x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B8%7D%7D%2C%5C%3Ax%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B8%7D%7D%5Cfrac%7B-1%2B%5Csqrt%7B3%7Di%7D%7B2%7D%2C%5C%3Ax%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B8%7D%7D%5Cfrac%7B-1-%5Csqrt%7B3%7Di%7D%7B2%7D)
So,
Therefore,
Any value other than the values will not be a solution of .
Keywords: solution, value
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