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GalinKa [24]
4 years ago
7

A regular triangular pyramid has a base area of 31.5 mm2 and a surface area of

Mathematics
1 answer:
Virty [35]4 years ago
6 0

Answer:

A) 220.5 mm^2

Step-by-step explanation:

<u>Explanation</u>:-

Given A regular triangular pyramid has a base of area is 31.5mm^2

and also given surface area of triangular pyramid is 252 mm ^2

by using formula

surface area of  regular triangular pyramid = base of area + half of lateral surface.

surface area = area of the pyramid X \frac{1}{2} lateral surface

252 = 31.5 + \frac{1}{2} lateral surface

252-31.5= \frac{1}{2} lateral surface

220.5 = lateral area of triangular pyramid

lateral area of triangular pyramid = 220.5 mm^2

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The original price of a plane ticket was reduce by 150 if p= the ticket original price in dollars which algebraic expression rep
77julia77 [94]

Answer:

p-150

Step-by-step explanatio

p=precio

reducido=150

se redujo, quiere decir que es "-"

Entonces dice "que expresión presenta el <u>precio reducido</u>"

Entonces sería:

(precio) - (reducido)

p-150

4 0
4 years ago
HELP ME PLEASE !!!!!!!
MaRussiya [10]
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6 0
3 years ago
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Determine the asymptotes of the function graphed below.
bagirrra123 [75]

Answer:

C

Step-by-step explanation:

Asymptote is basically a line that the graph approaches but NEVER cuts/crosses.

<em><u>Remember, x = a where a is a constant is an equation of a vertical line and x = b, where b is a constant, is the equation of a horizontal line.</u></em>

<em><u /></em>

  • Looking at the graph, we can see that the curve doesn't cross an imaginary line at  x = 0, this is a vertical asymptote.
  • Also, we can see that the curve doesn't cross an imaginary line at y = -2, this is a horizontal asymptote.

Looking at the answer choices, the choice C is right.

3 0
4 years ago
X/-3-50=0 PLEASE HELP
Pachacha [2.7K]

Hello!

First of all, let's add 50 to both sides.

x/-3=50

Now we multiply both sides by -3.

x= -150

I hope this helps!

3 0
3 years ago
Find the value of the test statistic z using zequalsStartFraction ModifyingAbove p with caret minus p Over StartRoot StartFracti
il63 [147K]

Answer:

C. 2.937

Step-by-step explanation:

Given the following :

H0 : p = 0.25

H1 : p > 0.25

Number of observations (n) = 647

p' = 30% = 0.3

SD = sqrt[(p(1 - p) / n)]

1 - p = 1 - 0.25 = 0.75

SD = sqrt[(0.25 * 0.75) / 647]

SD = sqrt[0.0002897]

SD = 0.0170234

Z = (p' - p) / SD

Z = (0.3 - 0.25) / 0.0170234

Z = 0.05 / 0.0170234

Z = 2.9371187 = 2.937

5 0
3 years ago
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