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ivanzaharov [21]

2 years ago

6

Can somebody help me solve this problem .

2 answers:

aleksandrvk [35]2 years ago

7 0

Answer:

b = 40

Step-by-step explanation:

You want your discriminant to be zero because then you have exactly one solution.

Solve b²-4ac = 0

=>

b² - 4·400 = 0

b = ±√1600

so b=±40

but f(-20) also has to be 0

so b=40 remains as the solution

padilas [110]2 years ago

5 0

Answer:

b = 40

Step-by-step explanation:

If x = - 20 is a zero of f(x) then f(- 20) = 0 , that is

(- 20)² - 20b + 400 = 0

400 - 20b + 400 = 0

800 - 20b = 0 ( subtract 800 from both sides )

- 20b = - 800 ( divide both sides by - 20 )

b = 40

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Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

2 years ago

Use the figure to determine the intersection of planes EAB and EFG

vredina [299]

Answer:

Option (3). EF

Step-by-step explanation:

From the figure attached,

Plane defined by EAB can be represented by the face EABF of the square prism also.

Similarly, plane EFG can be represented by the face EFGH of the prism.

Now these sides EABF and EFGH are joining each other at the edge EF of the cuboid.

Therefore, intersection of the given planes is EF.

Option (3) will be the answer.

7 0

3 years ago

I need help finding the answers someone plz help

Harlamova29_29 [7]

Happy New Year from MrBillDoesMath!

Answer:

Proof by ASA congruence postulate. See below

Discussion:

Fact 1 : angle A = angle T (given)

Fact 2: The angles on both sides of point X are equal as vertical angles

are equal.

From these facts it follows that angle M = angle H (as all plane triangles have 180 degrees). Also AM = TH (given) so

In the left triangle In the right triangle

(angle M, side AM, angle A) = (angle H, side TH, angle T)

Hence the triangles have two congruent angles, and congruent sides included between the angles, so they are congruent by ASA.

Thank you,

MrB

8 0

2 years ago

Use the Pythagorean Theorem to find the distance to the nearest tenth, between F(9, 5) and G(-2, 2). (Hint: Place F and G on the

artcher [175]

Put a point H on (9, 2). Sketch a triangle out of the three points. Distance between (-2, 2) and (9, 2) is going to be 11. Distance between (9, 2) and (9, 5) is going to be 3. These correspond to the a and b of the Pythagorean Theorem
c^2=a^2+b^2
c=√11^2+3^2=√130
<span>Square root of 130 is 11.4</span>

6 0

3 years ago

Juan bought a piece of lumberthat is 20 feet long.

Semmy [17]

Answer:mutiply not sure

Step-by-step explanation:

7 0

2 years ago