Ask question

Ask question

All categories

4 years ago

14

Is these answers correct ? Can you guys please help

1 answer:

sleet_krkn [62]4 years ago

4 0

It need to be more clear for me to read

You might be interested in

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

Solve each equation.<br> 1/3a = -5 a = ?<br> 12 - b = 12.5 b = ? <br> -0.1 = -10c c = ?

Rina8888 [55]

Answer:

a = -15, b = -.5, c = -1

Step-by-step explanation:

1/3a = -5 --> multiply each side with 3 --> a = -15

12 - b = 12.5 --> subtract 12 from both sides --> -b = .5 --> multiply each side with -1 to get b positive --> b = -.5

.1 = -10c --> multiply each side with -10 --> c = -1

8 0

3 years ago

Hassan made a vegetable salad with 2 3/8 pounds of tomatoes, 1 1/4 pounds of asparagus, and 2 7/8 pounds of potatoes. How many p

faltersainse [42]

Step-by-step explanation:

OK so

Tomatoes = 2 3/8 = 19/8 (turned into improper fraction)

Asparagus = 1 1/4 =5/4

Potatoes = 2 7/8 = 23/8

Total vegetables used =

19/8 + 5/4 + 23/8 = 42/8 + 5/4 = 42+10/8 =52/8

Answer is 52/8 = 6.5

<u>Answer :</u><u> </u><u>52</u><u>/</u><u>8</u><u> </u><u>pounds</u><u> </u><u>were</u><u> </u><u>used</u><u> </u><u>altogether</u>

3 0

2 years ago

Read 2 more answers

The weight, w, of a spring in pounds is given by 0.9 times the square root of the energy, E, stored by the spring in joules. If

alex41 [277]

Answer:

B) $w\approx3.12$ pounds

Step-by-step explanation:

$w=0.9\sqrt{E}$

$w=0.9\sqrt{12}$

$w\approx3.12$

6 0

2 years ago

How would you write an algebraic expression

ohaa [14]

I think it is:

1 cup = 26 grams of protein

s cups = 26 x s

26s

7 0

3 years ago