Answer:
2 m
Step-by-step explanation:
Here the area and the lengths of the two parallel sides of this trapezoid are given:
A = 7m^2, b1 = 3 m and b2 = 4 m. What's missing is the width of the trapezoid.
First we write out the formula for the area of a trapezoid:
b1 + b2
A = --------------- * w, where w represents the width of the figure.
2
We need to solve this for the width, w. Multiplying both sides of the above equation by
2
------------
b1 + b2
results in
2A
------------ = w
b1 + b2
Substituting 7 m^2 for A, 3 m for b1 and 4 m for b2 results in
2(7 m^2) 14 m^2
w = ------------------ = ---------------- = 2 m
(3 + 4) m 7 m
The missing dimension is the width of the figure. This width is 2 m.
angles BAC and BCA are equal = 69
69 +69 = 138
angles in a triangle =180
180-138 = 42
5x + 2 = 42
5x = 40
x = 8
Answer:
s = 6 inches
Step-by-step explanation:
Given:
r = 53 inches,
∠S = 6°
∠T = 58°.
Required:
Length of s
Solution:
Use Sine Rule
Thus:

<R = 180 - (58 + 6)
<R = 116°
r = 53 inches,
∠S = 6°
s = ?
Plug in the values

Multiply both sides by Sin(6)


(nearest inch)
<h3>
Answer: 24.5 </h3>
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Explanation:
It might help to draw it out. See the diagram below.
The base is JK which is 7 units long. I'm picking this as the base because this segment is completely horizontal.
Notice how the base JK spans from x = -3 to x = 4, which we can use subtraction and absolute value to get |J-K| = |-3-4| = 7.
The height is always perpendicular to the base. If the base is JK = 7, then the height is the vertical distance from K (or J) to L. This vertical distance is also 7 units. Subtract the y coordinates and apply absolute value. The base and height aren't always the same number.
Now we can find the area of the triangle
area = base*height/2
area = 7*7/2
area = 49/2
area = 24.5 square units