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3 years ago

6

The length of a rectangle is units greater than twice its width. If its width is w, which expression gives the perimeter of the

rectangle in terms of w?
2(w) + w
w + w
3w +
6w + 5

1 answer:

Vlada [557]3 years ago

7 0

The length is<span> twice its width so 2(w) + w is the answer</span>

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RSB [31]

<u>Given</u>:

Given that TUV is a right triangle.

The measure of ∠T is 16°

The length of VT is 4.9 feet.

We need to determine the length of TU.

<u>Length of TU:</u>

The length of TU can be determined using the trigonometric ratio.

Thus, we have;

$cos \ \theta=\frac{adj}{hyp}$

where $\theta=16^{\circ}$ , adj = TV and hyp = TU

Thus, we get;

$cos \ 16^{\circ}=\frac{4.9}{TU}$

Simplifying, we get;

$TU=\frac{4.9}{cos \ 16^{\circ}}$

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