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Feliz [49]
3 years ago
5

The longest side of the right triangle is 2 feet more than the middle side and the middle side is 1 foot less than twice the sho

rtest side. Find the length of the shortest side.
Mathematics
1 answer:
Ket [755]3 years ago
3 0
A right triangle's longest side is the hypotenuse
let x=longest, y=middle, and z=shortest
x=y+2
y=2z-1
therefore x=(2z-1)+2=2z+1
find z
z^2+y^2=x^2 by Pythagorean theorem
plug in x and y in terms of z
z^2+(2z-1)^2=(2z+1)^2
z^2+4z^2-4z+1=4z^2+4z+1
subtract the right-hand side's value from the left-hand side's
z^2-8z=0
z(z-8)=0
z=0, 8
z cannot be zero as the sides must have some value to it.
Therefore the shortest side is equal to 8
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Consider the function f(x) = 20/√x and its second-degree polynomial P2 (x) = 20 - 10(x-1) + 7.5(x-1)^2 at x=0.8. Compute the val
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According to the statement, f (x) = \frac{20}{\sqrt{x}}  and  P_{2}(x) = 20 - 10 (x-1) + 7.5 (x-1) ^ 2. Based on these definitions, at x=0.8 produce:

f (0.8) = \frac{20}{\sqrt {0.8}} = 22.3607.  On the other hand, you have to:

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