10 gallons equals how many liters
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Answer: The mean difference is between 799586.3 and 803257.9.
Step-by-step explanation: To estimate the mean difference for confidence interval:
Find the statistic sample:
- d = value of 6th - value of 13th;
- Sample mean of difference: mean = ∑d / n
- Sample standard deviation: s = ∑(d - mean)² / n - 1;
For the traffic count, mean = 1835.8 and s = 1382607.3
The confidence interval is 90%, so:
α =
α = 0.05
The degrees of dreedom are:
df = n - 1
df = 10 - 1
df = 9
Using a t-ditribution table, the t-score for α = 0.05 and df = 9 is: t = 1.833.
Error will be:
E =
E = 1.833.()
E = 801422.1
The interval is: mean - E < μ < E + mean
1835.8 - 801422.1 < μ < 1835.8+801422.1
-799586.3 < μ < 803257.9
The estimate mean difference in trafic count between 6th and 13th using 90% level of confidence is between 799586.3 and 803257.9.