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kirill [66]
2 years ago
8

What is the proportion used to solve: 160 of what numbers is 144

Mathematics
1 answer:
Ivanshal [37]2 years ago
7 0
Anawer would be 144 x 61 of the scale propor factor of 12 mark brainlist
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Last month, a dwarf lemon tree grew half as much as a semi-dwarf lemon tree. A full-size lemon tree grew three times as much as
dimulka [17.4K]

Answer: the dwarf tree grew by 3 inches.

the semi dwarf tree grew by 6 inches.

the full size tree grew by 18 inches.

Step-by-step explanation:

Let x represent how much the semi-dwarf lemon tree grew.

Last month, a dwarf lemon tree grew half as much as a semi-dwarf lemon tree. This means that the amount by which the dwarf lemon tree grew is expressed as x/2

A full-size lemon tree grew three times as much as the semi-dwarf lemon. This means that the amount by which the full-size lemon tree grew is expressed as 3x

Together, the three trees grew 27 inches. This means that

x/2 + x + 3x = 27

Cross multiplying by 2, it becomes

x + 2x + 6x = 54

9x = 54

x = 54/9

x = 6 inches

The dwarf tree grew by 6/2 = 3 inches.

The full-size lemon tree grew by 3 × 6 = 18 inches

7 0
3 years ago
2 y - 8 / 3 equals a + 3 B / 4 solving for y
zhuklara [117]
-2x+5
I am pretty sure
4 0
3 years ago
Can someone please explain how to figure this out!!
kakasveta [241]
2.9% OF the 500 phones are more than likely defective. In order to figure this out you must do 500*0.029 which would equal 14.5 and rounds off to 15. 15 out of the 500 phones will maybe be defective.
6 0
3 years ago
Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

8 0
2 years ago
Which is the graph of f(x)=4(1/2)^x
dusya [7]

It would be the first graph because it lands on -1 and +4

7 0
3 years ago
Read 2 more answers
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