Answer:
26 and 27
Step-by-step explanation:
Let the numbers be x and y
x + y = 53
xy = 702
x = 702/y
702/y + y = 53
Multiply through by y
702 + y^2 = 53y
y^2 - 53y + 702 = 0
y^2 - 27y - 26y + 702 = 0
y(y - 27) - 26(y - 27) = 0
(y - 27) (y - 26) = 0
y = 26 or 27
Solve for x in x + y = 53
if y = 26,
x = 53 - 26 = 27
if y = 27,
x = 53 - 27 = 26
The numbers are 26 and 27
Answer:
84
Step-by-step explanation:
I did math
The answer to this would be C because you can multiply everything by 3 and still have a consistent-dependent system.
Answer:
5 students are left out in the arrangement.
Step-by-step explanation:
If the number of rows = the number of columns
Then there must be an equal arrangement
Since the total number of students in the school is 2121
Then, the students that are left out in this arrangement = 2121 - (√2121 X √2121
Note the result of the square root would only consider the whole number, the digits after the decimal point signifies the remaining number that can't fit into the arrangement
so, √2121 = 46.05 (so 46 would be used)
= 2121 - (46 X 46)
= 2121 - 2116 = 5
Therefore 5 students are left out in the arrangement.
Answer:
f⁻¹(x) = (1/2)x +5
Step-by-step explanation:
In y = f(x), swap the variables, then solve for y. The expression you get is f⁻¹(x).
... y = 2x -10
... x = 2y -10 . . . . . . swapped variables
... x +10 = 2y . . . . . add 10
... (1/2)x + 5 = y . . . . divide by 2
... f⁻¹(x) = (1/2)x + 5 . . . . . . rewrite using function notation
