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zvonat [6]
3 years ago
11

Describe how to solve problems for the area of a reduced or enlarged figure when the scale factor and dimensions of the original

figure are given.
Mathematics
2 answers:
Nataly [62]3 years ago
3 0
Find the area of the original figure and multiply that by the square of the scale factor.
Marat540 [252]3 years ago
3 0

Answer:: To solve problems for the area of a reduced or enlarged figure, first square the scale factor. Then use the given dimensions to find the area of the original figure. Multiply the square of the scale factor by the area of the original to get the reduced or enlarged figure.

Step-by-step explanation:

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Which number is not a common factor of 32 and 48
Colt1911 [192]
5, 3, 7, 9 are all non-common factors
8 0
3 years ago
The mean value of 8 numbers is 17. Three of these numbers (9, 11, and 20) are discarded.
Viktor [21]

Answer:

19.2

Step-by-step explanation:

You get the mean of a set of numbers by adding them and dividing the sum by how many numbers there are.  In this case, you don't know what the individual 8 numbers are, but you can find out what they add up to.

Mean = (sum) / 8

17 = (sum) / 8

17 x 8 = sum

136 = sum

Now take out the numbers 9, 11, 20, which reduces the sum by 40.  There are 5 numbers left and they add up to 136 - 40 = 96.

The new mean is 96 / 5 = 19.2

3 0
3 years ago
Nine times the sum of a number and 26 is at most -25
kobusy [5.1K]

Answer:

x ≤  -259/9

Step-by-step explanation:

Change into a number equation   9(x + 26) ≤ -25

3 0
3 years ago
Can someone help me please. I can give you extra points. Message me or text me on snap anja4life. To help me with more please
Tju [1.3M]
<h3>Answer:  8</h3>

=====================================

Work Shown:

y = 192\left(4^{x-3}\right)\\\\196,608 = 192\left(4^{x-3}\right)\\\\\frac{196,608}{192} = 4^{x-3}\\\\1024 = 4^{x-3}\\\\4^{x-3} = 1024\\\\\log\left(4^{x-3}\right)=\log\left(1024\right)\\\\(x-3)*\log\left(4\right)=\log\left(1024\right)\\\\x-3=\frac{\log\left(1024\right)}{\log\left(4\right)}\\\\x-3=5\\\\x=5+3\\\\x=8\\\\

It will take 8 hours for the population to reach 196,608 bacteria.

3 0
2 years ago
How many solutions are there for the system x^2+4y^2=100 and 4y-x^2=-20
never [62]
There are 5 solutions for this system.

x^2 + 4y^2 = 100  ____1
4y - x^2 = -20  ____2
Add both 1 & 2 together. x^2 gets cancelled
4y^2 + 4y = 80   (send 80 to the other side and divide by 4)
Then equation the becomes : y^2 + y -20 =0
Now factorise the equation: (y+5) (y-4) = 0
Solve for y :  y = -5 and y = 4
Using the values of y to find the values of x. From equation 1:
x^2 = 100 - 4y^2    x = /100 - 4y^2  (/ means square root) Replace values of y
y = -5, x = /100 - 4(-5)^2 = /100 - 100 = 0
y = 4, x = /100 - 4(4)^2 = / 100 - 64 = /36 = -6 or 6
Thus we have 6 solutions y = -5, 4 and x = -6, 0, 6
6 0
3 years ago
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