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Whitepunk [10]
3 years ago
10

. A fishing bobber has a radius of 0.5 inch. Find the volume of the fishing bobber. Round your answer to the nearest tenth.

Mathematics
1 answer:
meriva3 years ago
5 0

Given:

The radius of the fishing bobber = 0.5 inch.

To find:

The volume of the find bobber.

Solution:

We know that the shape of fishing bobber is a sphere.

The volume of a sphere is:

V=\dfrac{4}{3}\pi r^3

Substitute r=0.5 and \pi=3.14 to find the volume of the fishing bobber.

V=\dfrac{4}{3}(3.14)(0.5)^3

V=\dfrac{4}{3}(3.14)(0.125)

V=0.52333...

Approx the value to the nearest tenth.

V\approx 0.5

Therefore, the volume of the fishing bobber is 0.5 cubic inches.

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Find x, y and ab and how to check if the answer is right ​
iris [78.8K]

Answer:

  x = 2, y = -2, AB = 142

Step-by-step explanation:

The fact that X is the midpoint gives you two relations:

  AX = XB

  AX + XB = AB

Since you have two unknowns, this number of equations is sufficient to find their values. Substituting the given expressions in the above equations, you have ...

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Simplifying the first of these can make simplifying the second one easier.

  24x +40 -3y +21 -22x = 5x +y +23 -4x +48

  2x -3y +61 = x +y +71 . . . . . . we can use this simplification

  x -4y = 10 . . . . . . . . . . . . . . . . subtract x+y+61

Now, we can simplify the second equation to ...

  2x -3y +61 +x +y +71 = 2x -5y +128

  3x -2y +132 = 2x -5y +128 . . . . . simplify the left side

  x +3y = -4 . . . . . . . . . . . . . . . add -2x+5y-132

Then the two equations we need to solve are ...

  • x -4y = 10
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Subtracting the second from the first, we get

  -7y = 14

  y = -2

Substituting into the first of these simplified equations, we get

  x -4(-2) = 10 . . . . substitute for y

  x +8 = 10 . . . . . . .evaluate

  x = 2 . . . . . . . . . .subtract 8

So, the solution is (x, y) = (2, -2).

Now, the values of AX and XB are ...

  AX = 2x -3y +61 = 2·2 -3(-2) +61 = 71

  XB = x+y+71 = 2 +(-2) +71 = 71 . . . . . . . . matches AX, a good sign

  AB = 2x -5y +128 = 2·2 -5(-2) +128 = 142 . . . . = AX+XB, another good sign

The desired values are x = 2, y = -2, AB = 142.

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You check the answer by filling the values into the expressions given in the problem statement and seeing if you get consistent results. Here, we used the simplified expressions, rather than the original expressions, so if we did the simplification wrong, we may have the wrong answer. It is always best to use the original equations. (A machine solver working with the original equations confirms our result, so "confidence is high.")

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3 years ago
Subtract and write out in minutes and seconds 87 seconds from 100 seconds
alexandr402 [8]

Answer:

  00:13  mm:ss

Step-by-step explanation:

There are 60 seconds in a minute. This fact can be used to convert the time period(s) to minutes and seconds either before or after you do the subtraction.

<h3>Difference</h3>

It is often convenient to do arithmetic with all of the numbers having the same units. Here, we are given two values in seconds and asked for their difference.

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The difference between the two time periods is 0 minutes and 13 seconds.

<h3>Conversion</h3>

If you like, the numbers can be converted to minutes and seconds before the subtraction. Since there are 60 seconds in a minute, the number of minutes is found by dividing seconds by 60. The remainder is the number of seconds that will be added to the time in minutes:

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  100 seconds = ⌊100/60⌋ minutes + (100 mod 60) seconds

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Then the difference is found in the same way we would find a difference involving different variables. (A unit can be treated as though it were a variable.)

  (1 min 40 s) -(1 min 27 s) = (1 -1 min) + (40-27 s) = 0 min 13 s

The difference between the two time periods is 0 minutes and 13 seconds.

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Answer:

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Step-by-step explanation:

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Answer:

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