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Lady_Fox [76]
3 years ago
6

Does anybody know how to solve for “C”?.

Mathematics
1 answer:
Jobisdone [24]3 years ago
8 0

Answer:

c = (b+3a)/2

Step-by-step explanation:

<u>Solve for c:</u>

  • 1/ac = 2/ab - 3/bc

<u>Multiply both sides by abc:</u>

  • abc/ac = 2abc/ab - 3abc/bc
  • b = 2c - 3a
  • b + 3a = 2c
  • 2c = b + 3a
  • c = (b + 3a)/2
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Nonamiya [84]
2. x^2 +6x +8 = (x+4)(x+2)

3. x^2 -7x +12 = (x-4)(x-3)

4. g^2 -2g -24 = (g+4)(g-6)

hope helped 
8 0
3 years ago
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What is Permutations and Combinations?
marissa [1.9K]

Answer:

See below

Step-by-step explanation:

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

Permutation can be expressed in math as:

\displaystyle{_n P _r = \dfrac{n!}{(n-r)!} \ \ \ (n \geq r) }

where n is a number of total object and r is a number of selected object to arrange. Hence. n cannot be less than r.

Now let's see an example of permutation, suppose we have letter A, B and C. I'd like to know how many ways these words can be arranged:

Since there are 3 letters total and 3 selected letters to arrange then:

\displaystyle{_3 P _3 = \dfrac{3!}{(3-3)!}}\\\\\displaystyle{_3 P _3 = \dfrac{3 \times 2 \times 1}{0!}}\\\\\displaystyle{_3 P _3 = \dfrac{6}{1}}\\\\\displaystyle{_3 P _3 = 6}

Therefore, there are 6 ways to arrange the letters - we can also demonstrate visually:

ABC - 1

ACB - 2

BAC - 3

BCA - 4

CAB - 5

CBA - 6

Notice that if you do visually, you'll get the same answer as the calculation of permutation!

----

Combination can be expressed mathematically as:

\displaystyle{_n C _r = \dfrac{n!}{(n-r)!r!} = \dfrac{_n P _r}{r!} \ \ \ (n \geq r) }

The difference between permutation and combination is that you only find how many ways you can select object in combination. Therefore, no arrange and doesn't care about order, just ways to select.

Suppose we have same 3 letters: A, B and C. I want to find how many ways I can select these 3 letters:

Since there are 3 letters total and 3 selected letters:

\displaystyle{_3 C _3 = \dfrac{3!}{(3-3)!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{0!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{3!}}\\\\\displaystyle{_3 C _3 = 1}

Hence, there is only one way to select 3 letters. This makes sense because if you have 3 letters then you can only select 3 letters only one way.

5 0
2 years ago
How many times bigger is 80000000 than 20000
Elis [28]
Answer:
4000 times greater
8 0
3 years ago
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jeka57 [31]

Answer: what what! Confused

Step-by-step explanation:

6 0
2 years ago
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1 David buys 4 kg of apples from the supermarket for £1.60.
liberstina [14]

Answer:

£ 2.8

Step-by-step explanation:

4 kg = 1.60

1 kg= 1.6/4 = £0.4

7 kg = 0.4*7 = £2.8

4 0
3 years ago
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