With 5 elements in A={20,1,6,10,11}, there are 2^5=32 possible subsets, including
the null set, and A itself.
Any subset that is identical to A is NOT a proper subset.
Therefore there are 31 proper subsets, plus the subset {20,1,6,10,11}.
The subsets are:
null set {} (has no elements) ........total 1
{20},{1},{6},{10},{11}.......................total 5
{20,1},{20,6}...{10,11}.....................total 10
{20,1,6},{20,1,10},...{6,10,11}.........total 10
{20,1,6,10}...{1,6,10,11}.................total 5
{20,1,6,10,11}.................................total 1
Altogether 32 subsets.
Answer:
A
Step-by-step explanation:
the other answers are totally absurd.
Answer:
AB =
cm
Step-by-step explanation:
As we can see from the figure, BCDE is a square with each corner equal to 90°.
So that, BDE is a right triangle with corner BED equal to 90°
As BDE is a right triangle, according to Pythagoras theorem, we have:
cm
As the diagram s the cube, so that it can be seen that AD is perpendicular to the surface BCDE
=> AD is perpendicular to BD
=> ADB is the right triangle with corner ADB equal to 90°.
As ADB is the right triangle, ccording to Pythagoras theorem, we have:
cm
=>
cm
Conclusion: AB =
cm
Answer:
Both A and B
Step-by-step explanation:
Answer:
Tbh idk but i recommend u to get a tutor